Answer:
Step-by-step explanation:
Answer:
The gradient of the line passing through the points (4·a, -a) and (6·a, 5·a) is 3
Step-by-step explanation:
The gradient of a (straight) line given the 'x' and 'y' coordinates of two points on the line, (x₁, y₁), and (x₂, y₂) can be found using the following formula;
![The \ gradient \ of \ a \ line, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=The%20%5C%20gradient%20%5C%20of%20%5C%20a%20%5C%20line%2C%20%5C%2C%20m%20%3D%5Cdfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
The coordinates of two points on the given line are;
(4·a, -a), and (6·a, 5·a)
Therefore, we get;
![The \ gradient \ of \ the \ line =\dfrac{5\cdot a-(-a)}{6 \cdot a-4 \cdot a} = \dfrac{6\cdot a}{2 \cdot a} = 3](https://tex.z-dn.net/?f=The%20%5C%20gradient%20%5C%20of%20%5C%20the%20%5C%20line%20%20%3D%5Cdfrac%7B5%5Ccdot%20a-%28-a%29%7D%7B6%20%5Ccdot%20a-4%20%5Ccdot%20a%7D%20%3D%20%5Cdfrac%7B6%5Ccdot%20a%7D%7B2%20%5Ccdot%20a%7D%20%3D%203)
The gradient of the line = 3.
Answer:
20
Step-by-step explanation:
substitute first to get:
6 + (3·4 - 5)2
multiply 3 and 4 to get 12:
6 + (12 - 5)2
subtract 12 and 5 to get 7:
6 + 7(2)
multiply 7 and 2 to get 14
6 + 14 = 20
Step-by-step explanation:
![8 \times (10 + 7) = \bigg( \boxed{8 \times 10} \bigg)+ \bigg( \boxed{8 \times 7} \bigg)](https://tex.z-dn.net/?f=8%20%5Ctimes%20%2810%20%2B%207%29%20%3D%20%20%5Cbigg%28%20%5Cboxed%7B8%20%5Ctimes%2010%7D%20%20%5Cbigg%29%2B%20%20%5Cbigg%28%20%5Cboxed%7B8%20%5Ctimes%207%7D%20%5Cbigg%29)
Answer:
The first choice (m<1=m<2=72)
Step-by-step explanation:
Since <ABC is bisected by BD, it's split evenly in half. Divide 144 by 2 and you get 72