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fgiga [73]
3 years ago
10

10 - 9 x 24 = 8 x 6 Use PEMDAS

Mathematics
2 answers:
meriva3 years ago
7 0
I’m probably wrong but I’d say 206=48 cuz you do multiplication first leaving you with 10-216=48 then I subtracted 10 from 216 and got 206 then dropped the 48 and got 206=48 making it “No Solution” because they aren’t equal
mr_godi [17]3 years ago
6 0

Answer:

The equation is false

Step-by-step explanation:

10 - 9 x 24 = 8 x 6

Multiply

10 - 216 = 48

Add 216 to both sides of the equation

10 ≠ 244

False

Hope this was useful to you!

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Plzzzzzzzzzzzzz help
bija089 [108]

Answer:

i think it's circumference

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
a random sample of 4 claims are selected from a lot of 12 that has 3 nonconforming units. using the hypergeometric distribution
Sloan [31]

Answer:

The probability that the sample will contain exactly 0 nonconforming units is P=0.25.

The probability that the sample will contain exactly 1 nonconforming units is P=0.51.

.

Step-by-step explanation:

We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.

We can write the probability mass function as:

P(x=k)=\frac{\binom{K}{k}\binom{N-K}{n-k}}{\binom{N}{n}}

where k is the number of non-conforming units on the sample of n=4.

We can calculate the probability of getting no non-conforming units (k=0) as:

P(x=0)=\frac{\binom{3}{0}\binom{9}{4}}{\binom{12}{4}}=\frac{1*126}{495}=\frac{126}{495} = 0.25

We can calculate the probability of getting one non-conforming units (k=1) as:

P(x=1)=\frac{\binom{3}{1}\binom{9}{3}}{\binom{12}{4}}=\frac{3*84}{495}=\frac{252}{495} = 0.51

5 0
4 years ago
These two trapezoids are similar What is the correct way to complete the similarity statement?
pentagon [3]

Option A:

\mathrm{ABCD} \sim \mathrm{GFHE}

Solution:

ABCD and EGFH are two trapezoids.

To determine the correct way to tell the two trapezoids are similar.

Option A: \mathrm{ABCD} \sim \mathrm{GFHE}

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

Option B: \mathrm{ABCD} \sim \mathrm{EGFH}

In the given image length of AB ≠ EG.

So, \mathrm{ABCD} \sim \mathrm{EGFH} is the not the correct way to complete the statement.

Option C: \mathrm{ABCD} \sim \mathrm{FHEG}

In the given image length of AB ≠ FH.

So, \mathrm{ABCD} \sim \mathrm{FHEG} is the not the correct way to complete the statement.

Option D: \mathrm{ABCD} \sim \mathrm{HEGF}

In the given image length of AB ≠ HE.

So, \mathrm{ABCD} \sim \mathrm{HEGF} is the not the correct way to complete the statement.

Hence, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

3 0
3 years ago
The number 296 is 74 % of what number
uranmaximum [27]
Answer: 296 is 74% of 400.
3 0
3 years ago
Read 2 more answers
How many different ways can teams of four members be formed from a class of 20?
guapka [62]
Assuming you want to choose 4 people from the class of 20; 

Begin by using the combinations formula; 

20C4=4845 possibilities 

Hope I helped :) 
4 0
3 years ago
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