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Alekssandra [29.7K]
3 years ago
15

PLEASE HELP, WILL MARK BRAINLIEST

Mathematics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

(y-0)=-3(x-2)

Step-by-step explanation:

im not sure if this os correct but i tried

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Identify a pattern in the given list of number <br> 1,2,1,4,1,8,1 what’s the next number ?
Ipatiy [6.2K]
10
it looks like the pattern is 1, (x+2) x is the number before it
3 0
3 years ago
Help please thank you!
irga5000 [103]

Answer:

Step-by-step explanation:

W(-4,-10) lies on third quadrant.

M(-12,0) lies on second quadrant or can say in x axis

C(8,3) lies on first quadrant.

K(11,-5) lies on fourth quadrant.

8 0
3 years ago
Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
astraxan [27]

Answer: 4\sqrt{3} .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

D=\sqrt{(d-b)^2+(b-a)^2}

Distance between points (-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3}).

D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}

Hence, the correct option is 4\sqrt{3} .

3 0
3 years ago
What is 4 - 7/4x = 1/2? <br>Solve for x.
tia_tia [17]
When evaluating, you must combine like terms first, so subtract 4 from 1/2 then multiply that number by -7/4, this will give you the value of x.
4 0
3 years ago
Read 2 more answers
A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates
son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector =\frac{\theta}{360}X\pi R^2

Area of the smaller sector =\frac{\theta}{360}X\pi r^2

Area of shaded part =Area of the larger sector-Area of the smaller sector

=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)

From the diagram, R=10 Inch, r=10-7=3 Inch, \theta=95^\circ

Therefore, Area of the sector cleaned

=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches

7 0
3 years ago
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