Are you trying to distribute the b^4 or factor it?
b^4 [(2b^2) + b]
Distributed:
[2(b^6) + (b^5)]
Factored:
b^5 [2b + 1]
Answer: The first 6 terms are = 8, 10, 12,14,16,18
Step-by-step explanation:
The NTH term of an Arithmetic Sequence is given as
an = a1 + (n - 1 ) d
where a1 = First term given as 8 and
d= common difference given as 2
Therefore We have that
the first term
an = a1 + (n - 1 ) d = 8+(1-1) 2
a1= 8
second term=
an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2
= 8+ 2(1) = 10
3rd term
an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2
= 8+ 2(2)= 8 + 4=12
4th term
an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2
= 8+ 2(3)= 8+6=14
5th term
an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2
= 8+ 2(4)=8+ 8=16
6th term
an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2
= 8+ 2(5)=8 +10 =18
To find the average number of customers for dinner, use the simple ratio of 5 lunch customers for every 8 dinner customers.
Because there are 40 lunch customers, this is eight groups of five lunch customers. This means you will need 8 groups of 8 dinner customers to make it equivalent.
8 x 8 = 64
There is an average of 64 customers for dinner.
Half of all the integers are ... all of the positive "counting numbers".
The total number is infinite, so I can't list them here. But if you start at '1 '
and count, you can never name <em>ALL</em> of them, but you can name <em>as many</em>
of them as you want to.
You can check the following
C=4
C=5
C=11