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Klio2033 [76]
3 years ago
15

4/7 = x+3/21 A) x=9 B) x=15 C) x= 33 3/4 D) x=91 - Would it be A??

Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0
The answer is A x=9 4/7=x+3/21 So yes it would be A
gogolik [260]3 years ago
5 0
4/7 = 12/21
12/21 = x + 3/21
9/21 = x
Hope this helped!!

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None of these are correct....typo??
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How many solutions will the following system of linear equations have?
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For the answer to the question above, 
2x + 4y = –7 (1)
y = -1/2x + 5 (2)
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I hoipe my answer helped you. Feel free to ask more questions. Have a nice day!
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Step-by-step explanation:

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Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op
Anika [276]

Answer:

The probability that the maximum speed is at most 49 km/h is 0.8340.

Step-by-step explanation:

Let the random variable<em> </em><em>X</em> be defined as the maximum speed of a moped.

The random variable <em>X</em> is Normally distributed with mean, <em>μ</em> = 46.8 km/h and standard deviation, <em>σ</em> = 1.75 km/h.

To compute the probability of a Normally distributed random variable we first need to convert the raw score of the random variable to a standardized or <em>z</em>-score.

The formula to convert <em>X</em> into <em>z</em>-score is:

z=\frac{X-\mu}{\sigma}

Compute the probability that the maximum speed is at most 49 km/h as follows:

Apply continuity correction:

P (X ≤ 49) = P (X < 49 - 0.50)

                = P (X < 48.50)

                =P(\frac{X-\mu}{\sigma}

*Use a <em>z</em>-table for the probability.

Thus, the probability that the maximum speed is at most 49 km/h is 0.8340.

8 0
4 years ago
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