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Rainbow [258]
3 years ago
12

What is the answer to this question ? -7+17=

Mathematics
2 answers:
IRISSAK [1]3 years ago
3 0
Well -7+17 would equal 10. Hope this helps!
nydimaria [60]3 years ago
3 0
The answer is 10 ,

Help thyou helps!!
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.125 as a fraction .
Oduvanchick [21]

Answer:

1/8


Step-by-step explanation:


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3 years ago
Plzzzzzzz help quick i have 10 mins left!!!
kumpel [21]

Answer:

A)

O = 3S

While O is the number of ounces of meat

While S is the number of sandwiches

B)

S= O/3 = 18/3 = 6 Sandwiches

6 0
2 years ago
Anna enjoys dinner with her family at a restaurant in Washington, D.C. She leaves a 15% tip on the price of her meal. She also h
AnnZ [28]

Answer:

$22

Step-by-step explanation:

tax and the tip increase the price paid for the meal

she paid 15 + 10 = 25% more than the price of her meal

p = original price

1.15 x p = 27,50

p = 27.50 / 1.15 = 22

3 0
3 years ago
SAT Help
posledela
Well, their speeds are (V_1 is Jack's speed, and V_2 is Richard's.
V_1 = \frac{1}{5} houses/day \\ V_2 = \frac{1}{7} houses/day \\ V = V_1 + V_2 = \frac{1}{5}+\frac{1}{7} = \frac{7+5}{35} = \frac{12}{35}
They, together, can paint 12 houses in 35 days. To get a single house, we only have to calculate \frac{35}{12} which is very close to 3 (a bit below)
5 0
3 years ago
Read 2 more answers
Solve the rational function of (check image) and check for extraneous solutions
Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

\frac{5}{x}=\frac{4x+1}{x^2}

Solving the rational function

\frac{5}{x}=\frac{4x+1}{x^2}

Apply fraction across multiply: if \frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5x^2=x\left(4x+1\right)

Subtract x(4x+1) from both sides

5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)

Simplify

5x^2-x\left(4x+1\right)=0

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x=0\quad \mathrm{or}\quad \:x-1=0

Thus, the solution to the equation is:

x=0,\:x=1

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0
3 years ago
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