Answer:
4.969696 hours
Step-by-step explanation:
The distance traveled is shown through the following equations
Distance = velocity * time
This means that
4100=velocity*4
This means that ariplane 1 travles at 1025 km/hr
We can then subtract 200 from this to find that airplane two travels at a speed of 825 km/hr
Now we need to find how long it takes for that plane to travel 4100
So using the same equation
4100=825*time
Divison will tell us that the answer is around 4.9696 hours which is pretty much 5
A square is a square a trapezoid is a lot weirder <span />
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
Fractal Generating Function, is
f(z)=z²-3+2i
⇒f(0)=0²-3+2i
f(0)= -3+2i
⇒f(-3+2i)
=(-3+2i)²-3+2i
=9-4-12 i-3+2i
=2-10 i
⇒f(2-10i)
=(2-10i)²-3+2i
=4-100-40i-3+2i
= -38 i-99
So, First three output values of the fractal generating function are
1.⇒ -3+2i
2. ⇒ 2-10 i
3.⇒-38 i -99
