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Sauron [17]
3 years ago
15

Solve each question for the variable.

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

B. 237.15

explaination

264.98- 502.13

=B

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CAN SOMEONE HELP ME WITH THIS!!
DIA [1.3K]

Answer:

Number of dogs = 6

Number of burgers = 11

Step-by-step explanation:

Number of dogs = x

Number of burgers = 2x - 1

Cost of a dog = $ 1.50

Cost of 'x' dogs = 1.5x

Cost of a burger = $ 2

Cost of (2x - 1) burger = (2x -1) * 2 = 2x *2 - 1*2

                                    = 4x - 2

Total amount collected  = $ 31

1.5x + 4x - 2 = 31 {add 2 to both sides}

        1.5x + 4x = 31 + 2

      1.5x+ 4x  = 33

               5.5x = 33

                    x = 33/5.5

                   x = 6

Number of dogs  = 6

Number of burgers = 2*6 - 1 = 12 - 1 = 11

4 0
3 years ago
Solving distance problems- <br> 10 points
slega [8]

Answer:

1.  54 and 9/20 km

2. 80 mm

3. 1.142 mi

4.0.83333 cm

Step-by-step explanation:

Do them all  by the butterfly method.

5 0
2 years ago
56 is 80 percent of what number
monitta
Let us assume the number to be = x
Then
(80/100) * x = 56
4x/5 = 56
4x = 56 * 5
4x = 280
x = 280/4
  = 70
The value of the unknown number is 70. I hope the procedure is clear enough for you to understand. You can always use this method for solving similar problems in future without requiring any help from outside. Only thing that needs to be taken care of is the calculation part.
7 0
3 years ago
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which is the factorization of x3 8? (x 2)(x2 – 2x 4) (x – 2)(x2 2x 4) (x 2)(x2 – 2x 8) (x – 2)(x2 2x 8)
kobusy [5.1K]
Hello,
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Answer B

(x^3-2^3=(x-2)(x²+2x+4)
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3 0
3 years ago
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I know I haven't been on this app for a long time but can ya'll help me
kramer

Answer:

2774

Step-by-step explanation:

start by multiplying 2 by 7, the answer is 14 put the 1 above the 8 in 1387 then put the 4 under the equation, similar to addition. repeat but next time when you multiply 2 by 8 add the 1 (from the previous multiplication) to the answer under and put the 1 from 17 on top of the 3. you get it?

8 0
3 years ago
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