If a basketball was dropped 32 feet from a second floor of a home, how far would it rebound if it bounciness was
2 answers:
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Since the distance in between each plate is 90ft. We know from home to 1st is 90ft. To get to 2nd from first is also 90ft. So 90 + 90 is 180ft.
Now this question is weird because it could be asking how far would a baseball player would have to run to get to 1st then 2nd
Or
Could be asking the distance from Home to 2nd without going to 1st. So just a straight line from home to 2nd.
If that’s the case we need to use the Pythagorean theorem
Our setup would be 90^2 + 90^2 = c^2
Adding A and B will get us 16200. Now we need to divide to get to the other side. But C is squared. So we need to Square root 16200. Which is 127.28ft.
Now this question is weird because it could be asking how far would a baseball player would have to run to get to 1st then 2nd
Or
Could be asking the distance from Home to 2nd without going to 1st. So just a straight line from home to 2nd.
If that’s the case we need to use the Pythagorean theorem
Our setup would be 90^2 + 90^2 = c^2
Adding A and B will get us 16200. Now we need to divide to get to the other side. But C is squared. So we need to Square root 16200. Which is 127.28ft.