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3 years ago

Help me plz thx :Dok

Mathematics

2 answers:

navik [9.2K]3 years ago

5 0

the answer to 154 divided by 14 is 11

Sunny_sXe [5.5K]3 years ago

5 0

Answer:11

Step-by-step explanation:

you devide

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HELLO PLEASE HELP!! HAVE A GOOD DAY/NIGHT!!

aliina [53]

So, XZ= 7x+1 and PZ= 4x-1. To figure out XP we have to subtract those two.

(7x+1)-(4x-1)

3x-2

3(8)-2

24-2

XP=22

6 0

2 years ago

Read 2 more answers

My brother told me he will give me $.25 per day for 10 days OR he will give me $.01 then give me double the following day for 10

NARA [144]

Answer:

you will get more money if he gives you 1 cent per day then doubles it

Step-by-step explanation:

if your brother gives you 25 cents per day, at the end of 10 days you will have $2.50

if he gives you 1 cent per day then doubles it, this will be your daily earnings:

day 1- 0.01

day 2- 0.02

day 3- 0.04

day 4- 0.08

day 5- 0.16

day 6- 0.32

day 7- 0.64

day 8- 1.28

day 9- 2.56

day 10- 5.12

then when you add all of this up, you would recieve 10.23 cents at the end of day 10

4 0

2 years ago

Luego de dormir 6 horas al día a usted le quedan 18, que puede repartir entre estudio y ocio. X representa

Kryger [21]

¿puede por favor hablar inglés

4 0

2 years ago

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58-by-58 squar

Savatey [412]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a = (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

4 0

3 years ago

I don’t get it. <br> Use the net to find the lateral area of the prism.

sesenic [268]

the net is pretty much the net of a long box, kinda like the one in the example in the picture below. Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.

now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.

we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.

$\bf \stackrel{\textit{two rectangles, left and right}}{2(3\cdot 15)}+\stackrel{\textit{two rectangles, front and back}}{2(6\cdot 15)}
\\\\\\
90+180\implies 270$

6 0

3 years ago