Jenny has $400 in an account with an annual interest rate of 6% compounded annually. if jenny makes no deposits or withdrawals,
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A table can be used to find the rate of change by giving you a visual representation of how the operation changes over time for example in the link i'm about to post you can see how much more money is earned as more cars are washed, it is showing how much money is being made OVER TIME, hope this helps :)
now to answer your second question, say you would like to know how many miles Tracy ran over a course of 2 hours, the x axis would be the miles and the y axis would be the time, then you would plot the different points on the graph showing the rate at which she is running
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to answer your last question a linear interval would be a sequence of numbers that when places on a number line they will form a line, a nonlinear interval is a sequence of numbers that don't make a line because there are inequities meaning the numbers in the sequence are all over the place
Hope this helps and i will post the pictures so you can have a visual representaion
now to answer your second question, say you would like to know how many miles Tracy ran over a course of 2 hours, the x axis would be the miles and the y axis would be the time, then you would plot the different points on the graph showing the rate at which she is running
'
to answer your last question a linear interval would be a sequence of numbers that when places on a number line they will form a line, a nonlinear interval is a sequence of numbers that don't make a line because there are inequities meaning the numbers in the sequence are all over the place
Hope this helps and i will post the pictures so you can have a visual representaion
Hi there!
v = ±
- - - - - - - - -
K = 1/2mv²
Isolate for the variable "v". We can begin by dividing both sides by 1/2. (Multiply by the reciprocal, or 2):
2 · K = 2 · (1/2mv²)
2K = mv²
Continue isolating by dividing both sides by "m":
2K / m = v²
Take the square root of both sides. Remember that the solution can either be positive or negative since there are positive and negative roots.
v = ±