Answer:
The volume of the figure is ![(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid
step 1
Find the volume of the cone
The volume of the cone is equal to

we have
----> the diagonal of the square base of pyramid is equal to the diameter of the cone

substitute

step 2
Find the volume of the square pyramid
The volume of the pyramid is equal to

where
B is the area of the base
h is the height of the pyramid
we have


substitute


step 3
Find the volume of the figure
![\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cpi%20%28l%29%5E%7B3%7D%5C%20units%5E%7B3%7D-%5Cfrac%7B1%7D%7B3%7Dl%5E%7B3%7D%5C%20units%5E%7B3%7D%3D%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
You would need to see the rest of the equation to plug in 7 for x. Treat it as y=equation and replace any x with 7.
I think the answer would be 1.8
Set up a system of equations.
X+y=6
Y-x =40
Substitution method.
Y=6-x
(6-x)-x =40
6-2x=40
-2x=34
X= -17
Plug it back into the equation.
-17+y=6
Y=33
(-17,33) is one of the possible answers.
Answer:
-20
Step-by-step explanation:
-20