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Kazeer [188]
3 years ago
10

Look at the picture and plzzz help and give me the right answer

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

Below is the sequence of steps which are required to follow in order to have the expression in its simplified form.

Step 1

(875x^{5}y^{9})^{\frac{1}{3}}

Step 2

(125.7)^\frac{1}{3}.x^{\frac{3}{5}}.y^{\frac{9}{3}}

Step 3

(125)^{1/3}.(7)^{1/3}.x(^{\frac{3}{3}+\frac{2}{3}}).y^{3}}

Step 4

(5^{3} )^{\frac{1}{3}}.7^\frac{1}{3}.x^{(1+\frac{2}{3})}.y^{3}

Step 5

5^{1}.7^\frac{1}{3}.x^{1}.x^\frac{2}{3}.y^3

Step 6

5xy³(7^{\frac{1}{3} }x^{\frac{2}{3} })

Step 7

5xy³(7x^{2})\frac{1}{3}

Step 8

5xy³\sqrt[3]{7x^{2}}

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1. Segment A'B' is parallel to segment AB. What is the length of segment BB'?
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(b) The mean and standard deviation of the 25-question test are 5 and 2 respectively.

(c) The value of <em>x</em> is 0.34.

Step-by-step explanation:

The random variable <em>X </em>is defined as the number of correct answers given by a person who is guessing each answer on a 25-question exam.

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(a)

The random variable <em>X</em> has  finite number of independent trials (i.e. 25 questions). There are only two outcomes for each trial, i.e. Success = correct answer and Failure = wrong answer. Each trial has the same probability of success (, i.e. P (X) = 0.25).

Thus, the probability distribution of the random variable <em>X</em> is Binomial with parameters <em>n</em> = 25 and <em>p</em> = 0.20.

(b)

Compute the mean of the random variable <em>X</em> as follows:

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Compute the standard deviation of the random variable <em>X</em> as follows:

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It is provided that the minimum passing score foe the test is such that only 1% of students who are guessing will pass the test.

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Thus, the value of <em>x</em> is 0.34.

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