Here's one way to do it.
AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence
Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
Answer:
648pi
Step-by-step explanation:
V=pi*r^2*h
V=pi*9^2*8
V=pi*81*8
V=648pi
1) The set of words represented in the first task is definitely ''<span>member and class '' type of analogy. That's pretty easy, it reminds of definitions : simile is one of type of the figurative language and </span><span>isosceles is one of the types of triangles.
2) What about the next set, I am pretty sure that the gap should be filled with </span>jaywalking : offense :: bottle : container. I think that these words represent consequences, so jaywalking soneer or later will be spotted and it would have become an offence, and bottle will spent the rest of its life in the container.
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Hope that helps!</span>
