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3 years ago

Help me please ,Thanks

Mathematics

2 answers:

sweet [91]3 years ago

4 0

Your answer is D 1:6 Hope this helps :)

mylen [45]3 years ago

3 0

The answer would be D) 1:6, because there are 6 dimes and 36 coins altogether. 6:36 simplified down is 1:6. Hope this helped!

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Use f(x) = 1/2 x and f-^1(x) = 2x to solve the problems. f(2) = f(1) = f-^1 (F2)) =

balu736 [363]

Answer:

f(2) =

⇒ 1

f−1(1) =

⇒ 2

f−1(f(2)) =

⇒ 2

8 0

3 years ago

Solve : 4² ( 4³ ) with work shown

stepan [7]

Answer:

1024

Step-by-step explanation:

4²(4³)

4×4(4×4×4)

16(16×4)

16(64)

16×64

=1024

7 0

3 years ago

1. If your final exam counts as 20% of your semester grade in a class, and you have an 88% going into the final, what percent mu

zysi [14]

.8 (88%)+.2x=90%
70.4%+.2x=90%

subtract 70.4% from 90% to get 19.6%
make the .2x into 2 and the 19.6 into 196
divide 196 by 2 to come up with the answer of 98%.
you will need a 98% to have a 90% for the final grade

4 0

3 years ago

Read 2 more answers

The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle

ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use w to represent the width, the length will be 6 more than 2 times w.

Hence, the length is $2w+6$ .

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

$A=w(2w+6)$

We can also substitute 40 in for A as it's given in the question.

$40 = w(2w+6)$

Distributing w by multiplying it by both terms in the parentheses, we get

$40 = 2w^2+6w$

We can make the equation simpler by dividing both sides by 2.

$20 = w^2+3w$

Subtracting both sides by 20 will make the left-hand side 0.

$0=w^2+3w-20$

Now that we have put this quadratic equation into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

$w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}$

$w= \frac{-3\pm\sqrt{9+80}}{2}$

$w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}$

Since the second solution results in a negative number, it cannot be the length of w.

$w=\frac{-3+\sqrt{89}}{2}\approx3.217$

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

$l=2(3.217)+6$

$l=12.434$

The length of this rectangle is 12.434 cm.

6 0

2 years ago

a test has 20 multiple-choice questions with 5 choices each, followed by 35 true/false questions. if a student guesses on each q

Nuetrik [128]

Answer

There are 170 ways the student can answer the test.

Explanation

If there are 20 multiple-choice questions with 5 choices each, the student has 100 choices. The first question has 5 choices to pick from. The second has 5 as well. So does the third. Hopefully now you realize that you have to multiply the number of choices by the number of questions.

The same thing goes with the true/false questions. There are 2 choices for each true/false question, and there are 35 of those. 35×2 is 70. There are 70 ways to answer on the true/false questions.

Now combine the number of choices on the first part and the second part; 100+70 is 170.

3 0

3 years ago