3 units.
5:2 or 5/2 is the scale factor.
4,0 is the centre of dilation.
Answer: -19r + 31.7s i think
Step-by-step explanation:
<h2>
Answer: A.</h2>
Step-by-step explanation:
<em>Victoria's recipe:</em>
<em />
<em>170g of butter = 250 g of flour</em>
<em />
<em>1 g of butter = 250 ÷ 170 = 25/17 g of flour</em>
<em />
<em />
<em>Daughter's recipe:</em>
<em />
<em>340 g of butter = 400 g of flour</em>
<em />
<em>1 g of butter = 400 ÷ 340 = 20/17 of flour</em>
<em />
<em />
<em>Compare:</em>
<em />
<em>20/17 < 25/17 </em>
<em />
<em>⇒ Daughter uses less flour in her cookies</em>
<em />
<em>⇒ the cookies are more dense</em>
<em>So therefor, the correct answer is A. They have too much butter :) </em>
<em>* </em><em>Hopefully this helps:) Mark me the brainliest:)!!!!</em>
Answer:
Step-by-step explanation:
a)
![\int\limits^2_1 {\frac{1}{x(lnx)^p} } \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7B%5Cfrac%7B1%7D%7Bx%28lnx%29%5Ep%7D%20%7D%20%5C%2C%20dx)
this can be done by substitute lnx = u
dx/x = du
When x =1, u =0 and when x =2, u = ln 2
So integral = ![\int\limits^{ln2} _0 {du/u^p} \\\=\frac{u^{-p+1} }{-p+1}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7Bln2%7D%20_0%20%7Bdu%2Fu%5Ep%7D%20%5C%5C%5C%3D%5Cfrac%7Bu%5E%7B-p%2B1%7D%20%7D%7B-p%2B1%7D)
We find that this integral value is not definid for p =1
Hence for values of p other than 1, this converges.
When we substitute limits
![\frac{1}{1-p} ((ln2)^{1-p} -1)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B1-p%7D%20%28%28ln2%29%5E%7B1-p%7D%20-1%29)
and converges for p ≠1
b) ![\int\limits^1_0 {lnx}/x^p \, dx \\\int \frac{\ln \left(x\right)}{x^p}dx=\frac{1}{-p+1}x^{-p+1}\ln \left(x\right)-\frac{x^{-p+1}}{\left(-p+1\right)^2}+C](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7Blnx%7D%2Fx%5Ep%20%5C%2C%20dx%20%5C%5C%5Cint%20%5Cfrac%7B%5Cln%20%5Cleft%28x%5Cright%29%7D%7Bx%5Ep%7Ddx%3D%5Cfrac%7B1%7D%7B-p%2B1%7Dx%5E%7B-p%2B1%7D%5Cln%20%5Cleft%28x%5Cright%29-%5Cfrac%7Bx%5E%7B-p%2B1%7D%7D%7B%5Cleft%28-p%2B1%5Cright%29%5E2%7D%2BC)
So not converging for p =1
But ln x is defined only for x >0
So integral 0 to 1 makes this integral not valid and hence not convergent.