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castortr0y [4]
3 years ago
6

I need help on this question.

Mathematics
2 answers:
Ray Of Light [21]3 years ago
4 0

Remark

In order for the figure to be a parallelogram, the 2 parts of the same diagonal must be equal.

Equation

Therefore 79 - y = 2y + 22         Add y to both sides.

Solution

79 = 2y + y + 22                          Combine

79 = 3y + 22                                 Subtract 22 from both sides

79 - 22 = 3y                                 Combine like terms

57 = 3y                                         Divide by 3 on both sides

57/3 = y                                        Divide

19 = y

Answer y must be 19

Edit

For x you would have to obey the same principle.

3x + 1 = x + 27      Subtract x from both sides

3x - x + 1= 27       Combine like terms

2x + 1 = 27            Subtract 1 from both sides

2x= 27 - 1             Combine the right

2x = 26                Divide by 2 on both sides.

2x/2 = 26/2  

x = 13

enot [183]3 years ago
3 0

I am pretty sure y would be 79

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antoniya [11.8K]

answer= x=20

Step-by-step explanation:

We have, 35% × x = 7

or,  

35

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Multiplying both sides by 100 and dividing both sides by 35,

we have x = 7 ×  

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35

x = 20

If you are using a calculator, simply enter 7×100÷35, which will give you the answer.

5 0
2 years ago
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Answer:

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<em>Step by step explanation:</em>

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2 years ago
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Natasha_Volkova [10]
Next time please indicate which problem you want to work on.

One example of an equation with variables present on both sides is

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Or, given the numeric value of y-b and that of x-a, you could obtain the slope of the line thru the points (x,y) and (a,b).
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2 years ago
2. Write a quadratic function that has -intercepts (- 3, 0) and (4, 0) and passes through the point (5, 8)
Reptile [31]

Answer:

f(x)=x^2-x-12

Step-by-step explanation:

<u>Quadratic Function</u>

Standard Form of Quadratic Function

The standard representation of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

When the zeros of f (x1 and x2) are given, it can be written as:

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Where a is a constant called the leading coefficient.

We are given the two roots of f: x1=-3 and x2=4, thus:

f(x)=a(x+3)(x-4)

We also know that f(5)=8, thus:

f(5)=a(5+3)(5-4)=8

Operating:

a(8)(1)=8

Solving:

a=1

The function is:

f(x)=1(x+3)(x-4)

Operating:

\boxed{f(x)=x^2-x-12}

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2 years ago
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seropon [69]
More than one liter because it only depends how bog your sink is...I believe it is more than one liter
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