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3 years ago

I need help on this question.

Mathematics

2 answers:

Ray Of Light [21]3 years ago

4 0

Remark

In order for the figure to be a parallelogram, the 2 parts of the same diagonal must be equal.

Equation

Therefore 79 - y = 2y + 22 Add y to both sides.

Solution

79 = 2y + y + 22 Combine

79 = 3y + 22 Subtract 22 from both sides

79 - 22 = 3y Combine like terms

57 = 3y Divide by 3 on both sides

57/3 = y Divide

19 = y

Answer y must be 19

Edit

For x you would have to obey the same principle.

3x + 1 = x + 27 Subtract x from both sides

3x - x + 1= 27 Combine like terms

2x + 1 = 27 Subtract 1 from both sides

2x= 27 - 1 Combine the right

2x = 26 Divide by 2 on both sides.

2x/2 = 26/2

x = 13

enot [183]3 years ago

3 0

I am pretty sure y would be 79

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3 years ago

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andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
$\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}$

where:

The divisor = 2x -3

Using the long division method, we have:

$\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}$

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

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2 years ago

Explain why 2a+3b=5ab

Ahat [919]

That's not correct. The terms 2a and 3b are not like terms, so we cannot combine them to get 5ab. We simply leave it as 2a+3b.

If you had 2a+3a, then it would simplify to 5a

Similarly, 2b+3b = 5b

Or you could have 2ab+3ab = 5ab

The key is that the variable portions must match up to be able to add them.

8 0

3 years ago

Read 2 more answers

One lap around the school track is 5/8 of a mile Carin ran 3 1/2 laps how far did she run

bearhunter [10]

Given length of a lap = 5/8 mile.

Number of laps Carin ran = 3 1/2 laps.

3 1/2 can be read as 3 and a half. In improper fractions, it can be written as

(3*2+1)/2 = 7/2 laps.

In order to find the total distance covered in 3 1/2 or 7/2 laps, we need to multiply length of a lap by total number of laps ran.

Therefore, total distance covered = 7/2 × 5/8.

= $\frac{7}{2}\times\frac{5}{8}$

Multiplying across, we get

= $\frac{7\times5}{2\times8}$

= $\frac{35}{16}$

Let us convert 35/16 into mixed fractions.

On dividing 35 by 16, we get 2 quotient and 3 remainder.

So, the mixed fraction would be 2 3/16.

Therefore, she ran 2 3/16 miles in 3 1/2 laps.

4 0

3 years ago