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motikmotik
3 years ago
14

We found that Juan’s investment account can be modeled by the function, c(x) = 7x2 - 6x + 5, in thousands of dollars. What was J

uan’s initial investment?
$5
$10
$5,000
$10,000
Mathematics
2 answers:
anzhelika [568]3 years ago
4 0
Initial investment was when x=0, when no change had occured

c(0)=7(0)^2-6(0)+5
c(0)=5

this is in thousands
5*1000=5000
answer is $5000 is initial
nadezda [96]3 years ago
4 0

Answer:

Option (a) is correct.

The Juan’s initial investment is $ 5

Step-by-step explanation:

Given : Juan’s investment account can be modeled by the function,c(x)=7x^2-6x+5, in thousands of dollars.                        

We have to find the  Juan’s initial investment.

Since,  Juan’s investment is modeled by function

c(x)=7x^2-6x+5

Since initial investment is when he start the investment and is given by when

x = 0

Thus,  c(0)=7(0)^2-6(0)+5

Simplify , we get,

c(0) = 5

Thus, the Juan’s initial investment is $ 5

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Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and standard deviation of 1.00deg
IrinaVladis [17]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is the readings on thermometers. This variable is normally distributed with mean μ= 0 degrees C and standard deviation σ= 1.00 degrees C.

The objective is to find the readings that are in the top 3.3% of the distribution and the lowest 3.3% of the distribution.

Symbolically:

The lower value P(X≤a)=0.033

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(see attachment)

Lower value:

The accumulated probability until "a" is 0.03, since the variable has a normal distribution, to reach the value of temperature that has the lowest 3.3%, you have to work under the standard normal distribution.

First we look the Z value corresponding to 0.033 of probability:

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Now you reverste the standardization using the formula Z= (a-μ)/δ

a= (Z*δ)+μ

a= (-1.838*1)+0

a= -1.838

Top value:

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This value has 0.033 of the distribution above it then 1 - 0.033= 0.967

is below it.

You can rewrite the expression as:

P(X≤b)=0.967

Now you have to look the value of Z that corresponds to 0.967 of accumulated probability:

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The cutoff values that separates rejected thermometers from the others are -1.838 and 1.838 degrees C.

I hope it helps!

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3 years ago
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