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sergij07 [2.7K]
3 years ago
7

What is the standard form of this number? (8 0.1) + (5 * 0.01) + (1 x 0.001) =

Mathematics
1 answer:
Delicious77 [7]3 years ago
3 0

Answer:

0.851

Step-by-step explanation:

Multiply the numbers, add.

0.8 + 0.05 + 0.001 = 0.851.

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Tom received an allowance of $300 for his upcoming trip to Canada. He knows that he will spend $15 each day on food. Which equat
WARRIOR [948]

Answer:

m=15d-300

Step-by-step explanation:

4 0
3 years ago
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A certain substance in an experiment was being stored at −3.2°F. It was then placed on a table where the temperature was raised
tatuchka [14]

Answer:

−0.6°F

Step-by-step explanation:

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3 years ago
What is the sum of the areas of circle C and circle D?
Morgarella [4.7K]
Assuming that the center of each circle is at point C and D, then both have a radius of 7cm. We know that the formula for solving area of the circle is A=pi*r².
Then we solve area of once circle multiplied by two to get the total area of the given circles. The solution is shown below:
C1 area=3.1416*7²
C1 area=153.9384 cm²
Summation of the area of circle C and D is shown below:
Sum area=2*153.9384
Sum area=307.8768cm²

The answer is 98pi.
4 0
3 years ago
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Please help me i would appreciate it greatly
Lera25 [3.4K]

Answer:

I would put B

Sorry if it's wrong I would have to know what the test is about to answer this

Step-by-step explanation:

4 0
3 years ago
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In a recent year, a sample of grade 8 Washington State public school students taking a mathematics assessment test had a mean sc
Daniel [21]

Answer:

The  number is  N  =1147 students

Step-by-step explanation:

From the question we are told that

    The population mean is  \mu  =  281

     The standard deviation is  \sigma  =  34.4

    The sample size is  n = 2000

percentage of the would you expect to have a score between 250 and 305 is mathematically represented as

      P(250 <  X <  305 ) =  P(\frac{ 250 - 281}{34.4 }  <  \frac{X - \mu }{\sigma }  < \frac{ 305 - 281}{34.4 }   )

Generally  

             \frac{X - \mu }{\sigma }  =  Z  (Standardized \ value \  of  \  X )

So  

         P(250 <  X <  305 ) =  P(-0.9012<  Z

       P(250 <  X <  305 ) = P(z_2 < 0.698 ) -  P(z_1 <  -0.9012)

From the z table  the value of  P( z_2 < 0.698) =  0.75741

                                         and  P(z_1 < -0.9012) =  0.18374

     P(250 <  X <  305 ) = 0.75741 - 0.18374

      P(250 <  X <  305 ) =  0.57

The  percentage is  P(250 <  X <  305 ) =  57\%

The  number of students that will get this score is

           N  = 2000 * 0.57

           N  =1147

6 0
3 years ago
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