Answer:
0.5 mi (2640 feet)
Step-by-step explanation:
Answer:
Step-by-step explanation:
how many weeks are they doing this for?
Answer:
1 mile =1609 km
Step-by-step explanation:
Answer:
0.3678
Step-by-step explanation:
Jones figures that the total number of thousands of miles that an auto can be driven before it would need to be junked is an exponential random variable with parameter 1/20. Smith has a used car that he claims has been driven only 10,000 miles. If Jones purchases the car, what is the probability that she would get at least 20,000 additional miles out of it?
Given that the total number of thousands of miles(X) that an auto can be driven
before it would need to be junked is an exponential random variable with parameter 1/20.
=> X ≅ Exponential(λ= 1/20)
=> f(x) = 1/20 * e^(-x/20) , 0 < x < ∞
=> F(X) = P{X < x} = 1 - e^(-x/20)
The probability that she would get at least 20,000 additional miles out of it.
P{X > 20} = 1-P{X < 20}
P{X > 20} = 1-(1 - e^(-20/20))
= e^(-1)
= 0.3678
