<span>B) the bisectors of angles D, E, and F
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In an inscribed circle of a triangle, all angle bisectors will pass through the center of the circle.
Pls. see attachment.
1st attachment is Triangle DEF. 2nd attachment is how inscribed circle relates to the triangle it is inscribed in.
Answer: 128/15 min or 8.5 min
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You basically just switch it around and subtract the fractions
Answer: Having your students do speed drills is a way to help them learn quite fast.
Step-by-step explanation:
Answer:
AC Midpoint (2,0)-
CB Midpoint (5,-4)
midlength is 5
Step-by-step explanation:
midpoint formula ![(\frac{x_{1}+x_{2} }{2} ,\frac{y_{1} +y_{2} }{2})](https://tex.z-dn.net/?f=%28%5Cfrac%7Bx_%7B1%7D%2Bx_%7B2%7D%20%20%7D%7B2%7D%20%2C%5Cfrac%7By_%7B1%7D%20%2By_%7B2%7D%20%7D%7B2%7D%29)
A(2,4) C(2,-4)
![\frac{2+2}{2} =\frac{4}{2}=2\\\frac{4-4}{2} =\frac{0}{2} =0](https://tex.z-dn.net/?f=%5Cfrac%7B2%2B2%7D%7B2%7D%20%3D%5Cfrac%7B4%7D%7B2%7D%3D2%5C%5C%5Cfrac%7B4-4%7D%7B2%7D%20%20%3D%5Cfrac%7B0%7D%7B2%7D%20%3D0)
(2,0)
C(2,-4) B(8,-4)
![\frac{8+2}{2} =\frac{10}{2} =5](https://tex.z-dn.net/?f=%5Cfrac%7B8%2B2%7D%7B2%7D%20%3D%5Cfrac%7B10%7D%7B2%7D%20%3D5)
midpoint is (5,-4)
Distance between the 2 midpoints is the midsegment
(2,0) and (5,-4)
![d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1}) ^{2} }](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%20%2B%28y_%7B2%7D-y_%7B1%7D%29%20%20%5E%7B2%7D%20%20%20%7D)
![d=\sqrt{(5-2)^{2} +(-4-0)^{2} } \\d=\sqrt{3^{2} +(-4^{2})\\ } \\d=\sqrt{x} 9+16\\d=\sqrt{25} \\d=5](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285-2%29%5E%7B2%7D%20%2B%28-4-0%29%5E%7B2%7D%20%20%7D%20%5C%5Cd%3D%5Csqrt%7B3%5E%7B2%7D%20%2B%28-4%5E%7B2%7D%29%5C%5C%20%7D%20%5C%5Cd%3D%5Csqrt%7Bx%7D%209%2B16%5C%5Cd%3D%5Csqrt%7B25%7D%20%5C%5Cd%3D5)