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ladessa [460]
3 years ago
10

You are choosing between two health clubs. Club A offers membership for a fee of $28 plus a monthly fee of $24. Club B offers me

mbership for a fee of $35 plus a monthly fee of $17. After how many months will the total cost of health club A be at least the total cost for Club B
Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

The cost will be the same after 1 month

Step-by-step explanation:

Step 1: set up the equation

club A= 28x+24  club B= 35x+17

club A=club B: 28x+24=35x+17

Step 2: Get rid of the smallest X

28x+24=35x+17

-28         -28

24=7x+17

Step 3: Get rid of the constant next to the variable to isolate the variable

24=7x+17

-17       -17  

7=7x

Step 4: Inverse operation to remove variable

7÷7x=7x÷7x

1=1

I hope this helped, im not too good at explaining but im positive the solution is correct.

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What is x in 1/150/1/200x2=x
choli [55]

Answer:

6.66666667E-5

hope this helped a bit!

5 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Five more than a certain number is 11 less than double the number
kupik [55]

Answer:

The number is 16

Step-by-step explanation:

Five more than a certain number is 11 less than double the number

x+5 = 2x-11

11+5 = 2x-x

16 = x

5 0
3 years ago
Read 2 more answers
What is 6÷by a missing number =27?
Dimas [21]
6/x=27
times both sides by x
6=27x
divide both sides by 27
6/27=x
2/9=x

the missing number is 2/9
7 0
3 years ago
PLEASEEEE HELPPPPP!!!
Taya2010 [7]

(1, 3.5 ) and (3, 3.5 )

the endpoints of the midsegment are at the midpoints of DE and DF

using the midpoint formula with D(0, 7), E(2, 0), F(6, 0)

midpoint of DE = [\frac{1}{2}(0 + 2),\frac{1}{2}(7 + 0)] = (1, 3.5)

midpoint of DF = [\frac{1}{2}(0 + 6),\frac{1}{2}(7 + 0)] = (3, 3.5)


4 0
3 years ago
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