Answer:
33.
Step-by-step explanation:
8x + 4y = 44
4(2x + y) = 44
2x + y = 44/4 = 11.
6x + 3y
= 3(2x + y)
= 3 * 11
= 33.
727.29 + 248.50 − x ≥ 500;
x ≥ $475.79
727.29 + 248.50 − x ≤ 500;
x ≤ $475.79
727.29 − 248.50 + x ≥ 500
x ≥ $21.21
727.29 – 248.50 - x ≤ 500
x ≤ $21.21
Let x be the distance (in feet) along the road that the car has traveled and h be the distance (in feet) between the car
and the observer.
(a) Before the car passes the observer, we have dh/dt < 0; after it passes, we have dh/dt > 0. So at the instant it passes the observer we have
dh/dt = 0, given that dh/dt varies continuously since the car travels at a constant velocity.
