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larisa [96]
3 years ago
13

4. $545 at 4% for 2 years. What is it

Mathematics
1 answer:
inna [77]3 years ago
7 0
U should try using phone math it shows work too
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(5x2+10 to the third power)+10+7 show your work
balandron [24]
(5x2+10^3) +10+7 -> (10+1000) + 17 -> (1010) x 17 = 17,170
3 0
4 years ago
Rearrange the formulae to make x the subject:<br> ay/x - dx= wx <br> Thanks in advance
Lina20 [59]

Answer:

\frac{ay}{x}  - dx = wx

multiply x through out:

ay -  {dx}^{2}  = w {x}^{2}  \\  {wx}^{2}  +  {dx}^{2}  = ay

factorise out x²:

{x}^{2} (w + d) = ay \\  {x}^{2}  =  \frac{ay}{w + d}

take square root on both sides:

\sqrt{ {x}^{2} }  =  \sqrt{ \frac{ay}{w + d} }  \\  \\ x =  \sqrt{ \frac{ay}{w + d} }

3 0
3 years ago
Read 2 more answers
A worker has four different job offers, each with a contract for six years. Assuming the job descriptions are identical,
Phoenix [80]

9514 1404 393

Answer:

  $48,000 to start, with 6% raises

Step-by-step explanation:

The starting salaries are within a few percentage points of each other, so the majority of the difference in earnings will come because of the raises. The offer with the largest raise percentage is likely the best.

The earnings total can be figured as the sum of a geometric series with a first term of "starting salary" and a growth factor of (1+raise percentage). For starting salary 's' and raise percentage 'r', the total earnings in 6 years will be ...

  S = s((1+r)^6 -1)/r

Here are the total earnings, in thousands, for each of the offers:

  a) s = 49, r = .03, S = 316.95

  b) s = 51, r = .01, S = 313.75

  c) s = 48, r = .06, S = 334.82 . . . . best offer

  d) s = 50, r = .02, S = 315.41

The worker can earn the most from a starting salary of $48,000 and 6% increases each year.

7 0
3 years ago
Read 2 more answers
North side dormitory just purchased a new DVD player on sale for $416. The sale price was 80% of the original price. What was th
Diano4ka-milaya [45]
100 - 80% = 20 %
20% = $416
416 x 5 = $2080 = 100%
7 0
3 years ago
How would changes in sample size affect the margin of error, assuming all esle remained constant?
klasskru [66]

Answer:

A. A larger sample size would cause the interval to narrow.

Step-by-step explanation:

Sampling Error is error caused by observing sample instead of population. It is denoted by difference between population parameter (population mean) & sample statistic (sample mean).

Margin Error is a statistical measure of random sampling error in a survey results. High margin error implies less reliability of sample results to draw conclusion about population ; and less margin error implies more reliability of sample results to draw conclusion about population.

Margin error is inversely related to sample size : large sample size implies low margin error, and small sample size implies  high margin error. So, A larger sample size would cause the margin error interval to narrow.

7 0
4 years ago
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