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3 years ago

The quotient of 365.085 and 79.8

Mathematics

1 answer:

Paul [167]3 years ago

5 0

Answer:

4.575

Step-by-step explanation:

365.085/79.8=4.575

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Sarawong invests $7,371 in a savings

zvonat [6]

Answethere should be an answer key online

Step-by-step explanation:

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3 years ago

6.1 Practice Assignment Find the measure of angle 1? pls help

Svetlanka [38]

Answer:

79 degrees

Step-by-step explanation:

First, you want to find the interor angles.

Since there are 180 degrees in a triangle...180-(27+52)=101 degrees

And the bottom line is a straight line so it's equal to 180 degrees as well.

180-101=79 degrees

7 0

3 years ago

The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.

melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

The common ratio is: $\mathbf{r = \frac{a + 5d}{a + d}}$
The general term of the GP is: $\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

The nth term of an AP is:

$\mathbf{T_n = a + (n - 1)d}$

So, the 2nd, 6th and 8th terms of the AP are:

$\mathbf{T_2 = a + d}$

$\mathbf{T_6 = a + 5d}$

$\mathbf{T_8 = a + 7d}$

The first, second and third terms of the GP would be:

$\mathbf{a_1 = a + d}$

$\mathbf{a_2 = a + 5d}$

$\mathbf{a_3 = a + 7d}$

The common ratio (r) is calculated as:

$\mathbf{r = \frac{a_2}{a_1}}$

This gives

$\mathbf{r = \frac{a + 5d}{a + d}}$

The nth term of a GP is calculated using:

$\mathbf{a_n = a_1r^{n-1}}$

So, we have:

$\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

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3 years ago

5% of 40 pounds working out calculating the given percentage of a number

garri49 [273]

Answer:

5% of 40 is 2, 50% of fourth is twenty and so on.

Step-by-step explanation:

To get my ander which ios two i multiplied 5% x 40, the answer is 2.

5 0

3 years ago

MATH URGENT

maks197457 [2]

${x}^{2} + 4x - 12 = 0 \\ {x}^{2} + 4x + 4 - 4 - 12 = 0\\ {(x + 2)}^{2} - 16 = 0 \\ x = - + \sqrt{16} - 2 \\ x = + \: or - 4 - 2 \\ x = - 6 \: \: x = 2$
- subtract the 12 from both sides so that it becomes the last constant term in the quadratic equation which should now equal 0.
- take the 4x
- half the coefficient of 4 (2)
- square it (4)
- add it to the equation (+4)
- subtract it from the equation (-4)
- factorise the square (x+2)^2 expands to (x^2 + 4x + 2) as {a+b}^2={a^2 + ab + ba + b^2}
- now the equation is in turning point form.
- to find x, add 16 and square root 16 and (x+2)
- subtract 2 from positive or negative 4 (as -4^2 and 4^2 both equal 16).
- This should give you two values for x, -6 and 2.

I really hope that this helped :)

7 0

3 years ago