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nadezda [96]
4 years ago
6

the temperature is already at 40 degrees it rises 4.5 degrees per minute how long will it take to get to 76 degrees​

Mathematics
1 answer:
Andrei [34K]4 years ago
7 0

Answer:

It will take 8 minutes for the temperature to reach 76°

Step-by-step explanation:

The expression for the total temperature in degrees at time t can be written as;

T=I+EM

where;

T=total temperature

I=initial temperature

E=temperature increase per minute

M=number of minutes

This can also be written as;

total temperature=initial temperature+temperature increase per minute×number of minutes

In our case;

T=76°

I=40°

E=4.5°

M=m

replacing;

76=40+(4.5×m)

4.5 m=76-40=36

(4.5 m)/4.5=36/4.5

m=8

It will take 8 minutes for the temperature to reach 76°

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Step-by-step explanation:

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Step-by-step explanation:

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In an orchard, there are 6 apple trees for every 4 pear trees. Create a ratio table to determine the number of apple trees in th
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3 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Chuge%7B%7B%5Cmathfrak%7Bquestion%E0%BF%90%7D%7D%7D" id="TexFormula1" title="\huge{{\mathfra
kramer

Answer:

<h2><em><u>9</u></em></h2>

Step-by-step explanation :

\sqrt{ \frac{243}{3} }

=  \sqrt{81}

=  \sqrt{9 \times 9}

= <em><u>9(Ans)</u></em>

5 0
3 years ago
Read 2 more answers
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