What is 10 (3+8k) + 9 (k+3)
1 answer:
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Answer:
Step-by-step explanation:
By definition, and
. Since since
is negative,
must also be negative, and since
is positive, we must be in Quadrant II.
In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.
To find the remaining leg, use to the Pythagorean Theorem, where , where
is the hypotenuse, or longest side, of the right triangle and
and
are the two legs of the right triangle.
Solving, we get:
Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.
Thus, we have:
Answer:
595
Step-by-step explanation:
Let the first integer be n. Then each consecutive integer will be (n+1), (n+2)... until (n+16).
First, from the formula , where k is the number of elements and xk is the last element, we can find 1+2+3 ... +15+16 = (16/2)(1+16)=136.
Anyways, this means that 17n+136=306.
We can find that n=10
Thus, the first integer is 10, and the 17th integer will be 10+16=26.
Thus, the first integer immediately proceeding 26 is 27. There are a total of 17 digits including 27 so we can add 16 to 27 to find the last digit, which is 43. There are again 17 digits in this set.
Thus, we have: 17/2(27+43)=595.