The answer could be 5.4, 5 2/5, or 27/5.
Answer:
b) Bioremediation
Explanation:
The use of natural occuring or intentionally introduced micoorganisms to treat environmental pollutants is called as Bioremediation.
- Most of the bioremediation processes includes oxidation-reduction reaction.
- The natural degradation process of pollutants is improved by bioremediation.
- Green plant, Decomposers and their enzymes are used in bioremediation to imrprove the condition of the environment.
If its a dominant allele 75%
if its recessive allele 25%
thats what i was always taught i hope this helps some :)
The answer is C) 3/4
Let's analyze separately each of the traits:
Parental generation: AA x Aa
F1 generation: AA AA Aa Aa
So, all progeny will <span>phenotypically resemble the first parent.
</span>Parental generation: BB x bb
F1 generation: Bb Bb Bb Bb
So, all progeny will <span>phenotypically resemble the first parent.
</span>
Parental generation: Cc x Cc
<span>F1 generation: CC Cc Cc cc
</span>Only 3 (CC, Cc, Cc) out of 4 progeny will <span>phenotypically resemble the first parent.
The genotypes for first two traits will not affect </span>phenotypical resemblance to the first parent. So, it only counts the third trait, for which the chance to have progeny that <span>phenotypically resemble the first parent is 3/4.</span>
The question is incomplete as it does not have the options which are:
A) single-stranded complementary tails
B) blunt ends
C) poly-A sequences
D) 5' cap
E) interference
Answer:
A) single stranded complementary tails
Explanation:
Restriction endonuclease is the enzyme which cuts the DNA sequence in the internal sequence.
The endonuclease enzyme can cut the DNA sequence in a way that it can form the cuts with the single-stranded overhangs called sticky ends and without overhangs called blunt ends.
The sticky ends are produced when the enzyme makes cut at the single strand and then makes the cut at between the same base at the nitrogenous base. This type of asymmetrical cut forms the single-stranded overhangs which can form the complementary base pairs easily.
Thus, Option-A is correct.
