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3 years ago

How does a coronal mass ejection (CME) affect the solar wind?

Biology

1 answer:

brilliants [131]3 years ago

4 0

Answer:

Option A

Explanation:

Corona is defined by the strong magnetic fields. When these strong magnetic fields confine solar atmosphere and produces violent bubble of gases then it is said to cause coronal mass ejection (CME).

When a CME passes through the solar wind, it causes production of high velocity solar energetic particles that follow magnetic field lines and passes through the space between the Sun and the Earth. The charged particle added by CME intensifies the solar wind.

Hence, option A is correct

You might be interested in

Name the earth’s five major environmental spheres and state the defining characteristics of each

Ilya [14]

Hi

1. Lithosphere
2. Hydrosphere
3.atmosphere
4. Biosphere

The lithosphere/geosphere is made of the earth's core, the mantle, crust, ocean floor,mountains, sand, etc.The hydrosphere is made of everything water such as oceans, rivers, lakes, rain, and snow.The atmosphere is made of gasses such as oxygen, and hydrogen.Finally the biosphere is all that has life such as plants, animals, people, insects, etc.

3 0

3 years ago

One substance has no membrane transporters to move it but can diffuse freely through open leak channels if there is a concentrat

Rama09 [41]

Explanation:

Urea is a small nitrogenous compound which is the main end product of protein catabolism in mammals

Urea is a nitrogen-containing substance normally cleared from the blood by the kidney into the urine
It is made predominantly in the liver from ammonia and bicarbonate and is one of the main components of urine
The rate of synthesis varies from 300 to 600 mmol/day depending on the protein intake
All of this urea eventually finds its way into the urine
Because urea makes up a large part of the obligatory solute excretion, its osmotic pressure requires significant volumes of water to carry the urea
Urea passively crosses biological membranes, but its permeability is low because of its low solubility in the lipid bilayer
Some cells speed up this process through urea transporters, which move urea by facilitated diffusion
Urea is passively reabsorbed in the proximal tubule, but its route of transport is not clear
Urea transporters have not yet been identified for the proximal tubule

3 0

3 years ago

The process of ossification begins at a primary ossification center in both intramembranous and endochondral ossification. the p

AysviL [449]

The correct answer is true. Both intramembranous ossification and endochondral ossification originates from a primary ossification center. The primary ossification center, as the name implies, is the focus where the bone tissue starts ossifying. Primary ossification centers are usually found in the diaphysis of long bones or in the body of irregular bones.

7 0

3 years ago

What would be the main problem with reproduction if meiosis did not take place to form sex cells?

chubhunter [2.5K]

Explanation:

The answer is option a,b,c option d is incorrect I think this is multiple question.

5 0

3 years ago

In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The gene

NikAS [45]

Answer:

A) 9:3:3:1

B) All bitter fruit, yellow spotted offsprings

C) Phenotypes are bitter yellow spotted (4), bitter no spot (4), sweet yellow spot (4), and sweet no spot (4). 1:1:1:1

Explanation:

This is a typical dihybrid cross involving two genes, one coding for fruit taste and the other for spot color. The allele for bitter taste (B) and yellow spot (S) is dominant over the allele for sweet taste (b) and no spot (s) respectively.

Hence, a heterozygous F1 resulting from a cross between an homozygous dominant (bitter fruit, yellow spot) and homozygous recessive (sweet fruit, no spot) will have a BbSs genotype. The heterozygous F1 offsprings are self-crossed and produce gametes BS, Bs, bS, bs. (See punnet square). The F2 offsprings will have the following phenotypes: Bitter fruit, yellow spot (9)

Bitter fruit, no spot (3)

Sweet fruit, yellow spot (3)

Sweet fruit, no spot (1)

Back cross between a F1 offspring (BbSs) and homozygous dominant parent (BBSS) will produce all bitter fruit, yellow spot offsprings (see attached image). BBSS (4), BBSs (4), BbSS (4), and BbSs (4) are the offsprings' genotypes.

For the back cross between a F1 offspring (BbSs) and a homozygous recessive (bbss) parent, the Phenotypes with their proportions are as follows:

Bitter fruit, yellow spot (BbSs, 4)

Bitter fruit, no spot (Bbss, 4)

Sweet fruit, yellow spot (bbSs, 4)

Sweet fruit, no spot (bbss, 4).

4 0

3 years ago