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3 years ago

Can someone help me pls ?

Mathematics

2 answers:

PolarNik [594]3 years ago

5 0

The correct way to write 1/4% as a decimal is 0.0025.

The reporter's likely error was that he did not notice the percent sign, thus saying that 1/4% is equivalent to 0.25.

slava [35]3 years ago

3 0

Answer:

a. .0025 b. (see below)

Step-by-step explanation:

Percents are converted to decimals by moving the decimal 2 places to the left.

a. Write 1/4% as .25% Then, move the decimal two places to the left. You arrive at .0025.

b. The reporter's likely error is he/she thinking that 25 being 1/4 of one hundred, but it is not 1/4 percent of one hundred. It is 25% of one hundred.

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The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.

Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

$f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}$

The probability for exponential distribution is given as:

$P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}$

a) P( time between the next two calls will be 54 seconds or less)

$P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763$

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

b) P(time between the next two calls will be greater than 118.5 seconds)

$p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285$

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

6 0

4 years ago

Micheal earns $87 for 15 hours of part time work. How long must he work to earn $135

tatiyna

Answer:

23.28 hours

Step-by-step explanation:

He earns 5.8 per hour of part-time work. You can find this by doing 87/15
Because we now know that he earns 5.8 per hour we can just do 135/5.8 (23.28) < this is rounding to the nearest hundreth

3 0

3 years ago

For a track meet, Tara ran the 1,600 m event at constant speed in 5 minutes and 20 seconds. What was her speed?

Arlecino [84]

Distance ran by Tara = 1600 m

Time taken by Tara to ran 1600 m = 5 min 20 seconds

We have to calculate the speed.

Firstly, we will convert the unit of time in one unit.

Time = 5 min 20 seconds

= 5 min + $\frac{20}{60}$ min (Because 1 min = 60 sec)

= $5+\frac{1}{3}$

= $\frac{15+1}{3}$

= $\frac{16}{3}$ min

Now we will use Distance speed formula which states,

Distance = speed $\times$ time

1600 m = speed $\times$ $\frac{16}{3}$

speed = $\frac{1600 \times 3}{16}$

Speed = 300 m/min

So, the speed of Tara was 300 meter/min.

7 0

4 years ago

Can someone help me please

astra-53 [7]

Answer:

11. Jason needs to sell 35 bird feeders to make a profit of $135.
12. 80 guests must attend the picnic to pay for the permit.

8 0

3 years ago

Over the past month, a garment manufacturer produced 800 dresses. The distribution of the amount of fabric required to make the

son4ous [18]

Answer:

Yes it will be appropriate to model the distribution of a sample mean with a normal model

Step-by-step explanation:

Given that the population is not normal, and the sample is sufficiently large, according to the Central Limit theorem, the distribution of the mean pf the sampling distribution will be approximately normal not withstanding the population from which the sample is obtained. Therefore, the mean, $\overline x$ , and the standard deviation, $\dfrac{\sigma}{\sqrt{n} }$ , of the sample will be equal to the mean, μ, and standard deviation, σ, of the of the population

Therefore, it will be appropriate to model the distribution of a sample mean with a normal model

6 0

3 years ago

Read 2 more answers