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3 years ago

Find the values for a and b that would make the equality true. 4(ax^2 -5x+3)=8x^2 +bx+12

Mathematics

2 answers:

tankabanditka [31]3 years ago

5 0

Answer:

a 2 and b -20

Step-by-step explanation:

yawa3891 [41]3 years ago

4 0

Answer:

a = 2 and b = -20

Step-by-step explanation:

4(ax^2 -5x+3)=8x^2 +bx+12 should be multiplied out. Next, we equate the coefficients of the several powers of x:

4ax² - 20x + 12 = 8x² + bx + 12

Then 4a = 8, so a = 2

and -20 = b

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lana [24]

Answer: The area of the sector formed by central angle AOB is 5/8 th of the total area of the circle.

Step-by-step explanation:

Let r be the radius of the circle having the center O,

⇒ The area of the circle = $\pi r^2$ square unit.

And, the central angle AOB = $\frac{5\pi}{4}\text{ radian}$

$=(\frac{5\pi}{4}\times \frac{180}{\pi})^{\circ}$ ( since, $\pi$ = 180° )

$=(\frac{900}{4})^{\circ}$

$=225^{\circ}$

Hence, the area of sector AOB

$=\frac{225^{\circ}}{360^{\circ}}\times \pi r^2$

$=\frac{5}{8}\times \pi r^2$ square unit.

Now,

$\frac{\text{Area of sector AOB}}{\text{Area of circle}}=\frac{\frac{5}{8}\times \pi r^2}{\pi r^2}$

$=\frac{5}{8}$

⇒ Area of sector AOB = 5/8 × Area of the circle.

Hence, the area of the sector formed by central angle AOB is 5/8 th of the total area of the circle.

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3 years ago

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Sauron [17]

A = bh

12 = 4 × h [substitute A for 12 and b for h]

12 / 4 = h

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Therefore, h equals 4.

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siniylev [52]

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