Find the values for a and b that would make the equality true. 4(ax^2 -5x+3)=8x^2 +bx+12
2 answers:
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Plotting the data (attached photo) roughly shows that the data is skewed to the left. In other words, data is skewed negatively and that the long tail will be on the negative side of the peak.
In such a scenario, interquartile range is normally the best measure to compare variations of data.
Therefore, the last option is the best for the data provided.
In such a scenario, interquartile range is normally the best measure to compare variations of data.
Therefore, the last option is the best for the data provided.
Answer:
0
Step-by-step explanation:
This equation is in "vertex form," meaning that you can identify the vertex and other features of the graph from the equation.
y = a(x -h)² +k . . . . . the vertex is (h, k); the vertical scale factor is "a"
Comparing to your equation, you see ...
a = -1/2, h = 3, k = -1
The vertex is (h, k) = (3, -1). The vertical scale factor is negative.
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This tells you the graph opens downward (the scale factor is negative), and the vertex (maximum point) is below the x-axis. (It has a negative y-coordinate.)
Because it start below the x-axis and goes down from there, the graph does not intersect the x-axis. There are zero (0) x-intercepts.
