Answer:
horizontal shift left 5
Step-by-step explanation:
Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
SOH-CAH-TOA
sin=opp/hyp
cos=adj/hyp
tan=opp/adj
1. Sin c=opp/hyp 2. tan=opp/adj 3. sin=opp/hyp
sin c=8/17 tan38°=x/16 sin38=18/x
x=18/sin38; x=29.236846
Make an equation.
80% = 0.8
'of' is multiplication
'what number' is 'x'
'is' is an equal sign
0.8 * x = 64
0.8x = 64
Divide 0.8 to both sides:
x = 80