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gayaneshka [121]
2 years ago
13

The scale of a map says 4 cm represents 5 km. What distance on the map in cm represents an actual distance of 4 km

Mathematics
1 answer:
Vilka [71]2 years ago
5 0

4cm : 5km

xcm : 4km

Cross multiply.

4 * 4 = 16

5 * x = 5x

5x = 16

x = 16/5

x = 3.2km

3.2km : 4km

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IRISSAK [1]
The answer to the question is 2

4 0
2 years ago
Y= 1/2x-4 and y= -2x-9 what is the solution of equations
azamat

Answer:

(x,y)=(-2,-5)

Step-by-step explanation:

y=1/2x-4

y=-2x-9

(y=) 1/2x-4=-2x-9

1/2x +2x=-9+4

1/2x +4/2x=-5

5/2x=-5

5x=-5*2

5x=-10

x=-2

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2 years ago
A car travels 17 miles on one gallon of gas
zmey [24]

When x =170, y =10, when x = 187, y = 1, when x = 204, y = 12, when x = 221, y = 13, when x = 238, y = 14, when x = 255, y = 15, when x = 272, y = 16, when x = 289, y = 17, when x = 306, y = 18, when x = 323, y = 19, when x = 340, y = 20,

Step-by-step explanation:

Step 1; Assume y is the gallons in the tank while x is the range of the car. We need to determine the equation relating the y to the x values in the given coordinates. x is the dependent value whereas y is the independent value i.e. the value of x depends on the value of y.

Step 2; As y increases, x also increases. For every extra gallon in the tank, the car can go another 17 miles. So with y as the amount of gas in the tank in gallons and x as the range of vehicle, we get;

x = 17y, this represents the relation between x and y.

To find the gallons in the tank, y = \frac{x}{17},

For x = 170, y = \frac{170}{17} = 10,

Similarly equating the values we get that when x = 187, y = 11,

when x = 204, y = 12,

when x = 221, y = 13,

when x = 238, y = 14,

when x = 255, y = 15,

when x = 272, y = 16,

when x = 289, y = 17,

when x = 306, y = 18,

when x = 323, y = 19,

when x = 340, y = 20,

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2 years ago
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Well 5.3 x 10 is 53.
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This answer would be -375
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