2×2 + 10 + 200 + 56
The order of operations requires the multiplication be done first.
= 4 + 10 + 200 + 56
The addition is done left to right.
= 14 + 200 + 56
= 214 + 56
= 270
Check the Wronskian determinant:
The determinant is not zero, so the solutions are indeed linearly independent.
The coordinates of the midpoint of AB is (4.5, -1.5)
We can find this by taking the average of each coordinate. The average of the x's (2 and 7) is 4.5, while the average of the y's (-4 and 1) is -1.5.
The coordinates of the midpoint of CD is (-5.5, 1)
We can find this by taking the average of the coordinates as we did in the first one. The average of the x's (-3 and -8) is -5.5, while the average of the y's (-2 and 4) is 1.
I´d say "d" is the distance from the eye to the wall.
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
Now you have 3 ecs and 3 variables.
alfa,B and "d"
Answer:
A
Step-by-step explanation:
