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3 years ago

I just need help to solve these steps.

1 answer:

6 0

I dont think the answer is 129 unless you typed the problem in wrong. Order of operations say to do everything inside the perenthesis first so you would do the 3*2 which is 6 then divide the 12 by 6 and you get 2. so your new equation is 8^2+9(2)-7. Next distribute the 9 to the 2 that is inside the perenthesis. Square root the 8 also. Now it is 49+18-7. The answer would be 60 ...?

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Ayudenme porfavorr, es un problema de razonamiento matematico

Evgesh-ka [11]

Answer:

Step-by-step explanation:

count them all together and the right triangles add an additional number of triangles so there are 16 altogether

plus I don't know how you would get the other answers because that is the only one that makes sense if you are including overlapping and stuff because there are technically only 3 triangles actually shown here without taking out any other lines or ignoring them but for your purposes there are 16

5 0

3 years ago

Pls help me! and no files and pls actually help me

crimeas [40]

Answer:

To find m ( slope) we'll use the Slope Formula:

$\boxed{\sf{Slope\:(m)}=\cfrac{y_2-y_1}{x_2-x_1}}$

<u>Subtract the numbers:-</u>

$\sf 7. \:m=\cfrac{4-2}{6-5} =\boxed{2}$

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$\sf 8.\: m=\cfrac{-1-3}{2-6} =\boxed{1}$

_______________

$\sf 9.\: m=\cfrac{-4-(-2)}{3-1} =\boxed{-1}$

_______________

$\sf 10.\: m=\cfrac{0-3}{0-(-3)} =\boxed{-1}$

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$\sf 11.\:m=\cfrac{4-2}{3-1} =\boxed{1}$

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$\sf 12.\: m=\cfrac{1-7}{2-5} =\boxed{2}$

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$\sf 13.\:m=\cfrac{11-9}{1-(-4)} =\boxed{\frac{2}{5}}$

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$\sf 14.\:m=\cfrac{2-3}{3-5} =\boxed{\frac{1}{2}}$

_______________

$\sf 15.\: m=\cfrac{11-5}{2-9} =\boxed{-\frac{6}{7}}$

_______________

$\sf 16.\: m=\cfrac{-7-\left(-6\right)}{8-13}=\boxed{\frac{1}{5}}$

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$\sf 17.\: m=\cfrac{4-4}{6-1} =\boxed{0}$

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$\sf 18. \: m=\cfrac{2-(-7)}{5-5}=$

↑ Undefined

___________________________________

6 0

3 years ago

PLEASE I DESPERATELY NEED HELP WITHH THIS!!!!!!! I’ll give brainless and extra points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Rina8888 [55]

Answer:

1. 4x + 6

2. -15x + 11

5. -x + 4

6. -4x + 7

9. 5x - 2

12. x + 16

Step-by-step explanation:

Remove the parenthesis for each one so everything's out in the open. Next, you group like terms. The numbers with variables on one side, and the other numbers on the other side. For example:

x + 3x - 2 + 8

Then, you combine like terms:

4x + 6

That's mostly how you do each one.

8 0

3 years ago

Find the missing length indicated?

kondor19780726 [428]

Answer:

D. 15

Step-by-step explanation:

Let the missing length be represented as x.

Thus:

(24 - x)/12 = x/20 => angle bisector theorem

Cross multiply

20(24 - x) = x(12)

480 - 20x = 12x

480 - 20x + 20x = 12x + 20x

480 = 32x

480/32 = 32x/32

15 = x

Missing length = x = 15

6 0

3 years ago

Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a

Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

$Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }$