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3 years ago

10

I just need help to solve these steps.

1 answer:

My name is Ann [436]3 years ago

6 0

I dont think the answer is 129 unless you typed the problem in wrong. Order of operations say to do everything inside the perenthesis first so you would do the 3*2 which is 6 then divide the 12 by 6 and you get 2. so your new equation is 8^2+9(2)-7. Next distribute the 9 to the 2 that is inside the perenthesis. Square root the 8 also. Now it is 49+18-7. The answer would be 60 ...?

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What are the factors of 37, 51, and 45? i just dont get it

o-na [289]

45=1,3,5,9,15,45 37=only 1 and 37 because it is prime. 51= 1,3,17,51

3 0

3 years ago

Helpppppp someone please

d1i1m1o1n [39]

Answer:

x=22/5

Step-by-step explanation:

multiply by 3 on both sides

7+x=6x-15

x=6x-22

-5x=-22

*-1 on both sides

5x=22

x=22/5

6 0

3 years ago

The possible error involved in measuring each dimension of a rectangular box is ±0.02 inches. The dimensions of the box are 8 in

Vlad [161]

Answer:

Step-by-step explanation:

Given

Possible dimension error is $\pm 0.02 in.$

length of box $L=8 in.$

Width $W=5 in.$

height $h=12 in.$

Volume V is given by

$V=LWh$

$dV=LWdh+LhdW+WhdL$

and it is given

$dL=dW=dh=\pm 0.02\ in.$

since error always add therefore

$dV=(8\times 5+5\times 12+8\times 12)\cdot 0.02$

$dV=3.92 in.^3$

Propagated error is $3.92 in.^3$

relative error $=\frac{dV}{V}$

$=\frac{3.92}{480}$

$=0.00816$

$=0.816 \%$

3 0

3 years ago

The weight of an object is equal to 3\4 of its own weight plus 3\4of a pound. What is the weight?

Phoenix [80]

Answer:

The weight of the object is 3 kg.

Step-by-step explanation:

<u>Step 1: </u>

Let object weight be x kg.

Now, as per the available data,

3/4 kg + 3/4 (x kg) = x kg

<u>Step 2: </u>

3/4 (1 + x) = x

1 + x = 4x/3

1 = x (4/3 - 1)

x = 1 / (1/3)

x = 3

Weight of Object is 3 kg.

<u>Step 3: </u>

Let's check if this value satisfies the first equation.

3/4 + 3/4 x 3 = 3/4 + 9/4 = 12/4 = 3

Hence proved.

8 0

4 years ago

PLEASE HELP ME WITH QUESTION 7<br> SHOW YOUR WORK

posledela

Answer:

(-2, 1) and (6, 1)

Step-by-step explanation:

The standard form equations for a hyperbola are ...

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2} = 1 \\\\\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2} = 1$

The first form opens horizontally; the second opens vertically. Further, the center-focus distance 'c' is given by ...

$c^2 = a^2 +b^2 \qquad\text{$c$ = distance from center to focus}$

The attached figure illustrates the relation between the various parameters and the features of the hyperbola.

__

<h3>7.</h3>

Using the above information and the information in the first attachment, we find ...

(h, k) = (2, 1)

a = 4, b = 2

The vertices are (h±a, k), so are (2±4, 1) = (-2, 1) and (6, 1).

__

The second attachment illustrates the hyperbola and its vertices.

3 0

2 years ago