<h2><em>each student requires 9m² of floor </em></h2><h2><em>and given the no. of students is 50
</em></h2><h2><em>So the total area of the room is 9m²X50=450m²
</em></h2><h2><em>Given the length of the room is 25m
</em></h2><h2><em>so the Breadth is =450/25=18m
</em></h2><h2><em>
</em></h2><h2><em>each student requires 108m³ of space </em></h2><h2><em>so total volume of the room is 108X50=5400m³
</em></h2><h2><em>we know that : Volume=Area X h
</em></h2><h2><em> so⇒5400=450Xh
</em></h2><h2><em> ⇒h=5400/450= 12m</em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>
3 - 4z - 4 = 3z - 2 - z
-4z - 1 = 2z - 2
2z + 4z = -1 + 2
6z = 1
z = 1/6
Hope this helps!
Can you confirm is hypotenuse should be AC...
ADB would make another right triangle if I am correct and you could use the pyth theorem to determine AB<span />
Answer:
A volcano ejected with an initial velocity of 304 feet per second.
The height in feet is given by the equation H=-16t^2+ 304t where t is the time in seconds.
We will use the equation that traces the path of the projectile to determine the following information:
1) The time it takes the projectile to reach its maximum height (using the vertex formula: t=-b/2a)
The equation; H = -16t^2 + 304t, a=-16; b=304
t = -304/2°(-16)
t = 9.5 sec to reach max height
2) The maximum height of the projectile (use the result from part 1 to find the maximum height of the projectile)
t = 9.5
H = -16(9.5^2) + 304(9.5)
h = = -1444 + 2888
h = 1444 ft is the max height
3) Find the time it takes the projectile to return to the ground. Assume that the projectile starts at height H=0.
-16t^2 + 304t = 0
factor out -16t
-16t(t - 19) = 0
t = 19 sec to reach the ground
Step-by-step explanation:
Answer:
Step-by-step explanation:
