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2 years ago

Solid potassium fluorine gas → solid potassium fluoride balanced

1 answer:

5 0

The balanced symbol equation for Solid potassium fluorine gas → solid potassium fluoride is 2 K + F₂ → 2 KF ⁻.

<h3>What is a balanced equation?</h3>

The reactants are on the left side of the arrow in a balanced equation, while the products are on the right.

The moles in a compound are indicated by the number in front of the chemical formula. Subscripts indicate the number of atoms in a single molecule (numbers below an atom).

Thus, the balanced equation is 2 K + F₂ → 2 KF ⁻.

Learn more about balanced equation

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When Mendeleev organized the elements by their _________, he noticed the properties of elements repeated.

Mama L [17]

I believe it should be when he arranged the elements by their atomic mass.

4 0

3 years ago

For an exothermic reaction at equilibrium, how will increasing the temperature affect Keq?

Sonja [21]

Question:

<em>For an exothermic reaction at equilibrium, how will increasing the temperature affect Keq?</em>

Answer:

<em>The reaction will proceed towards the liquid phase. Heat is on the reactant side of the equation. Lowering temperature will shift equilibrium left, creating more liquid water. A reaction that is exothermic releases heat, while an endothermic reaction absorbs heat.</em>

<em>If you increase the temperature, the position of equilibrium will move in such a way as to reduce the temperature again. It will do that by favouring the reaction which absorbs heat. In the equilibrium, that will be the back reaction because the forward reaction is exothermic.</em>

Hope this helps, have a good day. c;

8 0

3 years ago

One liter of oxygen gas at standard temperature and pressure has a mass of 1.43 g. The same volume of hydrogen gas under these c

Alchen [17]

Answer:

Indeed, the two samples should contain about the same number of gas particles. However, the molar mass of $\rm O_2\; (g)$ is larger than that of $\rm H_2\; (g)$ (by a factor of about $16$ .) Therefore, the mass of the $\rm O_2\; (g)$ sample is significantly larger than that of the $\rm H_2\; (g)$ sample.

Explanation:

The $\rm O_2\; (g)$ and the $\rm H_2\; (g)$ sample here are under the same pressure and temperature, and have the same volume. Indeed, if both gases are ideal, then by Avogadro's Law, the two samples would contain the same number of gas particles ( $\rm O_2\; (g)$ and $\rm H_2\; (g)$ molecules, respectively.) That is:

$n(\mathrm{O_2}) = n(\mathrm{H}_2)$ .

Note that the mass of a gas $m$ is different from the number of gas particles $n$ in it. In particular, if all particles in this gas have a molar mass of $M$ , then:

$m = n \cdot M$ .

In other words,

$m(\mathrm{O_2}) = n(\mathrm{O_2}) \cdot M(\mathrm{O_2})$ .
$m(\mathrm{H_2}) = n(\mathrm{H_2}) \cdot M(\mathrm{H_2})$ .

The ratio between the mass of the $\rm O_2\; (g)$ and that of the $\rm H_2\; (g)$ sample would be:

$\begin{aligned}& \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})} = \frac{n(\mathrm{O_2})\cdot M(\mathrm{O_2})}{n(\mathrm{H_2})\cdot M(\mathrm{H_2})}\end{aligned}$ .

Since $n(\mathrm{O_2}) = n(\mathrm{H}_2)$ by Avogadro's Law:

$\begin{aligned}& \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})} = \frac{n(\mathrm{O_2})\cdot M(\mathrm{O_2})}{n(\mathrm{H_2})\cdot M(\mathrm{H_2})} = \frac{M(\mathrm{O_2})}{M(\mathrm{H_2})}\end{aligned}$ .

Look up relative atomic mass data on a modern periodic table:

$\rm O$ : $15.999$ .
$\rm H$ : $1.008$ .

Therefore:

$M(\mathrm{O_2}) = 2 \times 15.999 \approx 31.998\; \rm g \cdot mol^{-1}$ .
$M(\mathrm{H_2}) = 2 \times 1.008 \approx 2.016\; \rm g \cdot mol^{-1}$ .

Verify whether $\begin{aligned}& \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})}= \frac{M(\mathrm{O_2})}{M(\mathrm{H_2})}\end{aligned}$ :

Left-hand side: $\displaystyle \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})}= \frac{1.43\; \rm g}{0.089\; \rm g} \approx 16.1$ .
Right-hand side: $\displaystyle \frac{M(\mathrm{O_2})}{M(\mathrm{H_2})}= \frac{31.998\; \rm g \cdot mol^{-1}}{2.016\; \rm g \cdot mol^{-1}} \approx 15.9$ .

Note that the mass of the $\rm H_2\; (g)$ sample comes with only two significant figures. The two sides of this equations would indeed be equal if both values are rounded to two significant figures.

7 0

3 years ago

Do you agree or disagree with the statement: "A rise of -7°C" means "a fall of 7°C"? Explain.

vazorg [7]

Answer:

i would agree

Explanation:

5 0

2 years ago

Choose the best tool for each scenario.

Mama L [17]

Answer:

a) Graph

b) Weight balance or gas syringe or upside-down measuring cylinder

Explanation:

a) Identifying a trend in temperature change over time - The best tool for this scenario is to represents the temperature daily, weekly, monthly or annually on graph to interpret the fluctuation in temperature owing to local seasonal changes and weather conditions

b) Measuring the mass of a product of a chemical reaction - If the product is solid or liquid then the balance is used to measure the mass. If the product is a gas, then gas syringe or upside-down measuring cylinder is used.

8 0

3 years ago