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solmaris [256]
2 years ago
6

Solid potassium fluorine gas → solid potassium fluoride balanced

Chemistry
1 answer:
vfiekz [6]2 years ago
5 0

The balanced symbol equation for Solid potassium fluorine gas → solid potassium fluoride is 2 K + F₂ → 2 KF ⁻.

<h3>What is a balanced equation?</h3>

The reactants are on the left side of the arrow in a balanced equation, while the products are on the right.

The moles in a compound are indicated by the number in front of the chemical formula. Subscripts indicate the number of atoms in a single molecule (numbers below an atom).

Thus, the balanced equation is 2 K + F₂ → 2 KF ⁻.

Learn more about balanced equation

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List four things that could happen to water used in watering a local golf course
spin [16.1K]

Explanation:

feed the grass

evaporate

reclaimed

fall in the sand( bunkers under ground)

if this does not help, please be more specific

3 0
3 years ago
the nickel-cadmium battery cell has a standard potential of 1.20 v. the cell reaction is 2 nio(oh)(s) cd(s) 2 h2o(l) → 2 ni(oh)2
JulsSmile [24]

The correct answer of gibbs free energy is -232 KJ.

ΔG = -nFE° = -2*96485*1.20 = -232 (kJ)

The Gibbs free energy of a system at any point in time is defined as its enthalpy minus the product of its temperature times its entropy. Because it is defined in terms of thermodynamic properties that are state functions, the system's Gibbs free energy is a state function. It is commonly referred to as free energy because it is readily available at all times. If necessary, the reaction can steal this energy without having to pay or work for it. The reaction between sodium chloride and water is regarded as spontaneous, and it has a negative G. When solid NaCl is immersed in water, it begins to dissociate on its own without any external assistance.

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8 0
1 year ago
Americium-241 is used in smoke detectors. it has a first order rate constant for radioactive decay of k=1.6×10−3yr−1. by contras
Helga [31]
This question is missing the part that actually asks the question. The questions that are asked are as follows:

(a) How much of a 1.00 mg sample of americium remains after 4 day? Express your answer using 2 significant figures.

(b) How much of a 1.00 mg sample of iodine remains after 4 days? Express your answer using 3 significant figures.

We can use the equation for a first order rate law to find the amount of material remaining after 4 days:

[A] = [A]₀e^(-kt)

[A]₀ = initial amount
k = rate constant
t = time
[A] = amount of material at time, t.

(a) For americium we begin with 1.00 mg of sample and must convert time to units of years, as our rate constant, k, is in units of yr⁻¹.

4 days x 1 year/365 days = 0.0110

A = (1.00)e^((-1.6x10^-3)(0.0110))
A = 1.0 mg

The decay of americium is so slow that no noticeable change occurs over 4 days.

(b) We can simply plug in the information of iodine-125 and solve for A:

A = (1.00)e^(-0.011 x 4)
A = 0.957 mg

Iodine-125 decays at a much faster rate than americium and after 4 days there will be a significant loss of mass.
7 0
3 years ago
What is 450 g of flour a measure of?
Marat540 [252]
The right answer is D - mass.
3 0
3 years ago
Read 2 more answers
What type of reaction is P4 + 3O2 = 2P2O3
valentina_108 [34]

Answer:

synthesis

Explanation:

hope this helps

4 0
3 years ago
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