Answer:
0.425 moles of P₂O₅.
Explanation:
As per given balanced equation, four moles of phosphorus reacts with five moles of oxygen to give two moles of P₂O₅.
As given that the initial moles of phosphorus taken = 0.97 moles
moles of phosphorus left after reaction = 0.12 moles
moles of phosphorus reacted = 0.97-0.12 = 0.85 moles
When four moles of P reacts they give two moles of P₂O₅.
when one mole of P will react to give =
0.85 moles of P will react to give = P₂O₅
-20.16 KJ of heat are released by the reaction of 25.0 g of Na2O2.
Explanation:
Given:
mass of Na2O2 = 25 grams
atomic mass of Na2O2 = 78 gram/mole
number of mole =
=
=0. 32 moles
The balanced equation for the reaction:
2 Na2O2(s) + 2 H2O(l) → 4 NaOH(aq) + O2(g) ∆Hο = −126 kJ
It can be seen that 126 KJ of energy is released when 2 moles of Na2O2 undergoes reaction.
similarly 0.3 moles of Na2O2 on reaction would give:
=
x =
= -20.16 KJ
Thus, - 20.16 KJ of energy will be released.