Answer:
Explanation:
<u>1. Word equation:</u>
- <em>mercury(II) oxide → mercury + oxygen </em>
<u>2. Balanced molecular equation:</u>
<u>3. Mole ratio</u>
Write the ratio of the coefficients of the substances that are object of the problem:

<u>4. Calculate the number of moles of O₂(g)</u>
Use the equation for ideal gases:

<u>5. Calculate the number of moles of HgO</u>

<u>6. Convert to mass</u>
- mass = # moles × molar mass
- molar mass of HgO: 216.591g/mol
- mass = 0.315mol × 216.591g/mol = 68.3g
7.5 is the answer. You have to move the decimal 2 places to the right.
Answer is: 4,4 grams <span>of carbon dioxide gas would be produced.
</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
m(CaCO₃) = 10 g.
n(CaCO₃) = 10 g ÷ 100 g/mol.
n(CaCO₃) = 0,1 mol.
From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
n(CO₂) = 0,1 mol.
m(CO₂) = n(CO₂) · M(CO₂).
m(CO₂) = 0,1 mol· 44 g/mol.
m(CO₂) = 4,4 g.
Answer: I think the right answer is c
<u>Answer:</u> The reaction order with respect to A is 'm'
<u>Explanation:</u>
Order of the reaction is the sum of the concentration of terms on which the rate of the reaction actually depends. It is equal to the sum of the exponents of the molar concentration in the rate law expression.
Elementary reactions the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical equation.
The given chemical equation follows:

The rate of the above reaction is given to us as:
![Rate=k[A]^m[B]^n](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5Em%5BB%5D%5En)
In the above rate law expression, the order with respect to the reactants is not equal to the stoichiometric coefficients. Thus, it is not an elementary reaction.
Order with respect to reactant A = m
Order with respect to reactant B = n
Hence, the reaction order with respect to A is 'm'