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solmaris [256]
3 years ago
6

Solid potassium fluorine gas → solid potassium fluoride balanced

Chemistry
1 answer:
vfiekz [6]3 years ago
5 0

The balanced symbol equation for Solid potassium fluorine gas → solid potassium fluoride is 2 K + F₂ → 2 KF ⁻.

<h3>What is a balanced equation?</h3>

The reactants are on the left side of the arrow in a balanced equation, while the products are on the right.

The moles in a compound are indicated by the number in front of the chemical formula. Subscripts indicate the number of atoms in a single molecule (numbers below an atom).

Thus, the balanced equation is 2 K + F₂ → 2 KF ⁻.

Learn more about balanced equation

brainly.com/question/7181548

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How many moles are there in 7.5 L Of H2
True [87]
So multiply number of moles x number of atoms/mole = 1.8066 x 10^24 atoms of H2. One mole of any gas at STP has a volume of 22.4 L. So first determine the number of moles of gas you have.
for example do 7
7.5 \div 22.4
that 's what I think
3 0
3 years ago
PLEASE ANSWER THIS FAST
Fofino [41]

Answer:

A and c MgSO4 and HNO3

8 0
3 years ago
Read 2 more answers
What does the roman numeral stand for in copper(1) oxide should it not be copper(II) oxide
photoshop1234 [79]

Answer:

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

Oxidation number of Cu =?

Cu₂O = 0

2Cu + O = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

2Cu = 2

Divide both side by 2

Cu = 2/2

Cu = 1

Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

Oxidation number of O = –2

Oxidation number of CuO = 0

Oxidation number of Cu =?

CuO = 0

Cu + O = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = 2

Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

From the above illustrations,

We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.

3 0
3 years ago
what is the total amount of energy required to remove the most loosely bound electron from each atom in a mole of gaseous Ca
Temka [501]

Answer:

589.8 kJ/mol

Explanation:

Let's consider the process in which <em>the most loosely bound electron from each atom in a mole atom of gaseous calcium is removed.</em>

Ca(g) + Energy ⇒ Ca¹⁺(g) + 1 e⁻

The energy involved in this process is known as First Ionization Energy. The First Ionization Energy for calcium is 589.8 kJ/mol.

5 0
3 years ago
Sort these elements into pairs that would most likely exhibit similar chemical properties. It doesn't matter which pair goes in
nikklg [1K]

<em>Answer:</em>

  •                           Na = Rb
  •                           Ne = Kr
  •                           O = Se

<em>Explanation:</em>

  • According to modern periodic table, the elements present in same group have same chemical properties , because they same valence shell electrons.

<em>Na and Rb:</em>

  • As these both elements are present in group one, so these are called Alkali metals. Almost all alkali metal have same chemical properties.

<em>Ne and Kr:</em>

  • Both these elements are present in group 18, called as noble gases.
  • They have same chemical properties like both are stable and are inert.

<em>O and Se:</em>

  • Both elements are present in group 16.
  • Both have same chemical properties.
  • Both have same valence shell electrons.
4 0
3 years ago
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