Answer:
105mL of 0.7500M of NaOH are required
Explanation:
Phosphoric acid, H₃PO₄, reacts with sodium hydroxide, NaOH, as follows:
H₃PO₄ + 3 NaOH → Na₃PO₄ + 3H₂O
<em>Where 1 mole of phosphoric acid reacts with 3 moles of NaOH</em>
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To solve this question we must find, as first, the moles of H3PO4 that react. Using the chemical equation we can find the moles of NaOH required to neutralize this acid. And, with its concentration, we can find the volume oof NaOH required:
<em>Moles H3PO4:</em>
35.00mL = 0.03500L * (0.7500mol / L) = 0.2625 moles H3PO4
<em>Moles NaOH:</em>
0.2625 moles H3PO4 * (3mol NaOH / 1mol H3PO4) = 0.07875 moles NaOH
<em>Volume NaOH:</em>
0.07875 moles NaOH * (1L / 0.7500mol) = 0.105L =
<h3>105mL of 0.7500M of NaOH are required</h3>
The temperatures of the gases will not be equal.
- The ideal gas law specifies the mechanical behavior of ideal gases. It is capable of calculating the volume of gases produced or consumed.
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In chemical equations, this equation is widely used to convert between volumes and molar quantities.
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The ideal gas law states that the pressure, temperature, and volume of gas are related to each other
∵V is the same for both
∴T= same for both.
When n increases, T decreases, so, n is 1 for hydrogen gas and 0.5 for oxygen gas ,implying that oxygen gas will have more temperature than hydrogen gas since its number of moles are lower than hydrogen gas.
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Explanation:
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