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Hunter-Best [27]
3 years ago
9

The prime factorization of a number is 3^2x5^3x7. Which statement is true about the factors of the number? ? Twenty-one is a fac

tor of the number because both 3 and 7 are prime factors. Twenty-one is not a factor of the number because 21 is not prime. Ninety is a factor of the number because 3^2=9 and 90 is divisible by 9. Ninety is not a factor of the number because 90 is not divisible by 7.
Mathematics
2 answers:
rodikova [14]3 years ago
7 0
The 1st statement is true.

21 is a factor because both 3 and 7 are factors.
olga_2 [115]3 years ago
6 0

Answer:

Twenty-one is a factor of the number because both 3 and 7 are prime factors.

Step-by-step explanation:

Given number is,

3^2\times 5^3\times 7

=3\times 3\times 5\times 5\times 5\times 7

Where, 3, 5 and 7 are prime numbers ( only divisible by 1 and itself ),

⇒ Both 3 and 7 are prime factors of the given number,

⇒ 21 is a factor of the given number.

Thus, first option is correct.

⇒ Second option is incorrect.

Now, 5 is factor of the given number but 2 is not,

⇒ 10 is not a factor of the given number,

⇒ 90 is not a factor of the given number,

⇒ Third option is incorrect.

Suppose 90 is divisible by 7,

⇒ 90 = 7a

Where a is any whole number,

⇒ 7=\frac{90}{a}

3^2\times 5^3\times 7=3^2\times 5^3\times \frac{90}{a}

Since, 90 could be a factor of this number, if a = 3 or 5 or their multiple,

For the other values of a, 90 can not be the factor,

Hence, there is no effect of divisibility of 90 by 7 on having 90 as a factor of the given number,

⇒ Fourth option is incorrect.

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Which vectors represent the reflection of the vector <3, -7> across the x-axis? A. [3/7} B. [-3/7] C. <-3, 7> D. &lt
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Answer:

D)    < 3, 7)>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given that the vector < 3 , -7 >

Given the vector reflection across the x-axis

                   (x,y) → (x , -y)

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Read 2 more answers
Show that 2x +1 is a factor of 2x3 +5x2+4x+1 and factories completely
larisa [96]

\text{According to the factor theorem, if f(b) = 0, then x-b is a factor of f(x).}\\\\\text{Given that,}\\\\f(x) = 2x^3 +5x^2 +4x +1 \\\\f\left(-\dfrac 12 \right) = 2\left( - \dfrac 12 \right)^3 +5 \left( - \dfrac 12 \right)^2 +4 \left( - \dfrac 12 \right) +1 \\\\\\~~~~~~~~~~~~=-2 \cdot \dfrac 18 + 5 \cdot \dfrac 14 -2 +1 \\\\\\~~~~~~~~~~~=\dfrac 54 -\dfrac14 -1\\\\\\~~~~~~~~~~~=\dfrac 44 -1 \\\\\\~~~~~~~~~~~=1-1\\\\\\~~~~~~~~~~~=0\\\\\text{So,}~ 2x +1 ~ \text{is a factor of f(x).}

\text{Now,}\\\\f(x) = 2x^3 +5x^2 +4x +1 \\\\~~~~~~=2x^3+x^2 +2x^2 +2x +2x+1\\\\~~~~~~=x^2(2x+1)  +2x(2x+1) +  (2x+1)\\\\~~~~~~=(2x+1)(x^2 +2x +1)\\\\~~~~~~=(2x+1)(x+1)^2

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Step-by-step explanation: It should be the second answer.

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3 years ago
Solve the equation 6/5y-10=-4<br> X=
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6/5y-10=-4

move -10 to the other side

sign changes from -10 to 10

6/5y-10+10= -4+10

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6/5(5/6)y=6(5/6)

Cross out 6/5 and 5/6 , divide by 5 and 6 then becomes y

Cross out 5 and 6 on the right side

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