Let s be Seth's age. let r be Romans age. 5 years ago Seth was s-5 and Roman was three times as old, or 3(s-5), or 3s-15=r-5
in ten years Seth will be s+10 and Roman will be twice as old, or 2(s+10), or 2s+20=r+10
3s-15 =r-5
r=3s-10
2s+20=r+10
r=2s+10
3s-10=2s+10
s=20
Seth is 20 years old
setting the two equations equal gives us
3(s-5)=2(s+10)
3s-15=2s+20
s=35
Hi there, I don't know if I am right but I will try to solve this, 10x+24=64, subtract 24 from both sides, 10x+24-24=64-24=10x=40, divide both sides by 10, 10x/10=40/10, x=4
At the end of 3 years, your savings will have grown to $483.
You will have earned in $83.17 in interest.
Answer:
Here is the ans hope it helps:)
Answer
with
Step-by-step explanation:
Statement Reasons
1.∠1 ≅ 4 Given
2.∠1 = ∠2 Being Vertically opposite angles.
3.∠4 = ∠3 Being Vertically opposite angles.
4.∠2 = 3 From Statement no 2 & 3, Transitive property.
5.∠2 ≅ 3 From Statement 4
Proved.