1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tanya [424]
3 years ago
15

How do you do c/6 = -4 I've tried but got confused.

Mathematics
1 answer:
Artyom0805 [142]3 years ago
7 0
<span>c/6 = -4
Multiply 6 on both sides
Final Answer: c= -24</span>
You might be interested in
Find the value of X
rosijanka [135]

Try this solution:

1) (6x-10)+(6x+10)=180;

12x=180;

2) x=15.

Answer: A

5 0
3 years ago
Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4
Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of  (-9,-8) and (7,-4)

midpoint formula is

\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}

\frac{-9+7}{2} ,\frac{-8+-4}{2}

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}

slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4  and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10


3 0
3 years ago
A shirt is on sale for 45% off the price. The cost of the shirt is $14.95. What is the price of the shirt now?
Pavlova-9 [17]

Answer:

$8.2225

Step-by-step explanation:

100% - 45% = 55%

then divide 55 by 100 to get .55

lastly multiply .55 to 14.95 to get 8.2225

3 0
3 years ago
Clare is paid $90 for 5 hours of work. At thos rate how many seconds does i take for her to earn 25 cents?
natka813 [3]

We are given

Clare is paid $90 for 5 hours of work

Total money paid =$90

total hours of work =5 hours

so, firstly  we will find rate of work

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

and we get

The rate of work is

=\frac{90}{5}

=18 $/ hour

now, we have to find time for amount paid is 25 cents

so, amount paid =25 cents

100 cents =1$

so, amount paid =$ 0.25

Since, the rate is constant

so, we can take same rate here

now, we can use formula

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

18=\frac{0.25}{T}

now, we can solve for T

T=\frac{0.25}{18} hour

since, T is in hours

so, we can change into seconds

1 hour =3600seconds

so, we can plug

T=\frac{0.25}{18}\times 3600 seconds

T=50 seconds......................Answer


6 0
3 years ago
True or false? The skeletal system provides a rigid framework for the body
MrRissso [65]
True the skeletal system shapes the body, like your shoulders and chest. 
8 0
3 years ago
Read 2 more answers
Other questions:
  • What is 7 minus f in algebraic expression
    15·1 answer
  • What values of c and d make the equation true? c = 1, d = 3 c = 1, d = 32 c = 2, d = 8 c = 2, d = 32
    7·2 answers
  • Anthony buys one pound of oranges for $12 and sells it for $14. How can he write the profit in his account book?
    9·1 answer
  • 45 divided into 9 what is the dividend
    7·1 answer
  • I need help with school
    7·1 answer
  • Think of a way you use Geometry or a way Geometry has improved your life. Write 2-3 sentences about the impact Geometry has on y
    7·1 answer
  • A tortoise is walking in the desert. It walks for
    9·1 answer
  • Complete the table:<br><br> a. 1<br> c. 2<br> b. -1<br> d. 0
    9·1 answer
  • Leo reads 10 pages in 1/3 hour. What is the unit rate for pages per hour? For hours per page. The unit rate is blank pages per h
    14·1 answer
  • How i can answer this question
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!