So,
We are trying to figure out when Grandpa Lopez's age was twice that of Dad.
Let x represent the number of years before/after when G. Lopez's age was twice that of Dad.
66 + x = 2(37 + x)
Distribute.
66 + x = 74 + 2x
Subtract x from both sides.
66 = 74 + x
Subtract 74 from both sides.
-8 = x
So 8 years ago, G. Lopez was twice as old as Dad. Let's check that.
66 - 8 = 58
37 = 8 = 29
29 * 2 = 58
58 = 58
It checks.
Answer:
43 and 56/12
Step-by-step explanation:
<span>First, group the x values together (on one side) and the other values on the other.
6x + 3 - 1/2 x = -2x +5
6x - 1/2 x + 2x = 5 - 3
Now solve!
7 and 1/2 x = 2
x = 8
Hope this helps!</span>
Answer:
it's being divided by -5
Step-by-step explanation:
-5m= -40
m=8
Answer:
J. -13-18
Step-by-step explanation:
J will give the value -31
