Answer:
50%
Explanation:
So the cross is hh x Hh
Making a punnet square would get Hh,hh,Hh,hh
The percent of babies that will have Hh is 50%
Answer:
The genotypes of the rooster and the chicken are homozygous and that of their offspring is heterozygous.
This case is called codominance, where the offspring receives an allele from each parent, from the rooster and the hen, because there is codominance, so neither allele is recessive and the phenotype of both alleles is expressed so the phenotype of the offspring is checkered.
We can say then that the chicken and the rooster have equal strength between their alleles. in the cases of codominance the laws of mendel do not apply.
Because warm air rises up so it's warmer on the top floor.
Answer:
0.0139- frequency of heterozygotes in the population
Explanation:
Let q to the power of 2 represents the frequency of the homozygous recessive (aa) = 1/20000 = 0.00005
This, q = √q^2 = √0.00005 = 0.007
Since p + q = 1
p = 1 - 0.007 = 0.993
Using the formula: p^2 + 2pq + q^2
Where 2pq represents the frequency of the heterozygotes, thing we have
2 x 0.007 x 0.993
= 0.0139
A thicker atmosphere, which would scatter more sunlight, make the sky look bluer and lower the air temperature.
