The solubility of Lead(II)Fluoride is 2.17 × 10⁻³ g/L in water at 25°C.
At a specific solution temperature, a solid salt compound can entirely dissolve in pure water up to a predetermined molar solubility limit. The dissociation stoichiometry ensures that the molarities of the constituent ions are proportionate to one another. The saturable nature of the solution causes them to also coexist in a solubility equilibrium with the solid component. At this temperature, a solubility product constant Ksp is calculated using the solubility product of their molarity values.
Lead (II) fluoride has the following solubility equilibrium for its saturated solution:
⇄ 
![K_s_p = [Pb^2^+][F^-]^2](https://tex.z-dn.net/?f=K_s_p%20%3D%20%5BPb%5E2%5E%2B%5D%5BF%5E-%5D%5E2)
This compound dissociates in a 1:2 ratio of ions. For the compound dissolved in pure water, the Ksp is expressed in terms of the molar solubility "x" as:
Here,
× 
4.1 × 10⁻⁸ = 4 x³
x³ = 1.025 × 10⁻⁸
x³ = 10.25 × 10⁻⁹
x = 2.17 × 10⁻³ g/L
Therefore, the solubility of Lead(II)Fluoride is 2.17 × 10⁻³ g/L.
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I believe the answer is mass :)
Explanation:
Chemical properties are those properties that tells us about what a substance can do as regards to whether or not the substance reacts with other substances.
- Chemical properties are a function of the electrons contained in an atom and how they interact with other atoms.
- Examples of chemical properties are:
- Flammability
- Rusting of iron
- Precipitation
- Decomposition of water by an electric current
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Answer:
The answer to your question is below
Explanation:
1) 0.143g of Mg into atoms
- Look for the atomic number of Magnesium in the Periodic table
Atomic number = 24.31 g
-Use the Avogadro's number to find the number of atoms
24.31g ------------------- 6.023 x 10²³ atoms
0.143 g ----------------- x
x = (0.143 x 6.023 x 10²³) / 24.31
x = 8.613 x 10²² / 24.31
x = 3.54 x 10²¹ atoms
2) 0.101 kg of Ti into atoms
-Look for the atomic number of Titanium in the Periodic table
Atomic number = 47.87 g
-Use the Avogadro's number to find the number of atoms
47.87 g --------------------- 6.023 x 10²³
101 g ---------------------- x
x = (101 x 6.023 x 10²³) / 47.87
x = 6.08x 10²⁵ / 47.87
x = 1.27 x 10²⁴ atoms
