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2 years ago

The change of phase from a vapor to a liquid is called _____. evaporation condensation distillation vaporization

2 answers:

5 0

Its condensation

the vapour has a lot of kinetic energy but if it cools down it loses that energy and condenses into a liquid

hope that helps

lesya [120]2 years ago

3 0

The answer is condensation. Hope this helps and have an amazing day. :)

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The metric system of units is known as

andre [41]

Answer:

International System of Units (SI)

Explanation:

I hope it helps :)

6 0

3 years ago

Compute the values of the diffusion coefficients for the interdiffusion of carbon in both α-iron (BCC) and γ-iron (FCC) at 900°C

bogdanovich [222]

Answer:

α-iron (BCC) has faster diffusion rate because of lower values in activation energy and pre-exponential value.

Explanation:

Taking each parameters or data at a time, we can determine the values/a constant for each parameters in the diffusion coefficient equation.

For α-iron (BCC), the diffusion coefficient = pre-exponential value,Ao × e^( -Activation energy,AE)/gas constant,R × Temperature.

Converting the given Temperature, that is 900°C to Kelvin which is equals to 1173.15K.

For α-iron (BCC), the pre-exponential value, Ao = 1.1 × 10^-6, and the activation energy, AE = 87400.

Thus, we have that the diffusion coefficient = 1.1 × 10^-6 × e(-87400)/1173.15 × 8.31.

Diffusion coefficient for α-iron (BCC) = 1.41 × 10^-10 m^2/s.

Also, For the γ-iron (FCC), the pre-exponential value, Ao = 2.3 × 10^-5 and the activation energy, AE = 148,00.

From these values we can see that both the exponential value, Ao and the activation energy for γ-iron (FCC) are higher than that of α-iron (BCC).

Thus, the diffusion coefficient for the γ-iron (FCC) = 2.3 × 10^-5 × e ^-(14800)/8.31 × 1173.15.

Then, the diffusion coefficient for the γ-iron (FCC) = 5.87 × 10^-12 m2/s.

Therefore, there will be faster diffusion in α-iron (BCC) because of lower activation energy and vice versa.

6 0

3 years ago

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid. HCl(aq), as described by

melisa1 [442]

Answer:

0.88 g

Explanation:

Using ideal gas equation to calculate the moles of chlorine gas produced as:-

$PV=nRT$

where,

P = pressure of the gas = 805 Torr

V = Volume of the gas = 235 mL = 0.235 L

T = Temperature of the gas = $25^oC=[25+273]K=298K$

R = Gas constant = $62.3637\text{torr}mol^{-1}K^{-1}$

n = number of moles of chlorine gas = ?

Putting values in above equation, we get:

$805torr\times 0.235L=n\times 62.3637\text{ torrHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{805\times 0.235}{62.3637\times 298}=0.01017\ mol$

According to the reaction:-

$MnO_2+4HCl\rightarrow MnCl_2+2H_2O+Cl_2$

1 mole of chlorine gas is produced when 1 mole of manganese dioxide undergoes reaction.

So,

0.01017 mole of chlorine gas is produced when 0.01017 mole of manganese dioxide undergoes reaction.

Moles of $MnO_2$ = 0.01017 moles

Molar mass of $MnO_2$ = 86.93685 g/mol

So,

$Mass=Moles\times Molar\ mass$

Applying values, we get that:-

$Mass=0.01017moles \times 86.93685\ g/mol=0.88\ g$

<u>0.88 g of $MnO_2(s)$ should be added to excess HCl (aq) to obtain 235 mL of $Cl_2(g)$ at 25 degrees C and 805 Torr.</u>

6 0

3 years ago

Calculate the volume of 4.50 mol of SO2 (g) measured at STP. At STP: P = 101.3 kPa, T = 273.15 K A. 87.3 L B. 101 L C. 127 L D.

miss Akunina [59]

Answer:

101L

Explanation:

We use the ideal gas relation

PV = nRT

P = pressure = 101.3KPa

V = volume = ?

n = number of moles = 4.5moles

T = Temperature = 273.15K

R = molar gas constant = 8.314J/mol.k

Rearranging the equation to make V the subject of the formula yields :

V = nRT/P

= ( 4.5 × 8.314 × 273.15) ÷ 101.3

= 10,219.361 ÷ 101.3 = 100.88L which is apprx 101L

8 0

3 years ago

What bond type is expected between C & H given that their electronegativity difference is 0.4?

Olenka [21]

Answer:

Since they have an electronegativity difference of 0.4 then they will form a Covalent Bond.

7 0

3 years ago