Answer:
1. C = 0.73 M.
2. pH = 0.14
Explanation:
The reaction is the following:
HCl + NH₃ ⇄ NH₄⁺Cl⁻
From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

Where "a" is for acid and "b" is for base.
The number of moles is:
Where "C" is for concentration and "V" for volume.


Hence the initial concentration of the acid is 0.73 M.
The original pH of the acid is given by:
![pH = -log([H^{+}])](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%28%5BH%5E%7B%2B%7D%5D%29%20)
Therefore, the original pH of the acid is 0.14.
I hope it helps you!
Using E=hν where h is Planck's constant and v is the frequency of the photon. In the question above,the wavelenght is given so we can find the frequency of the photon using c=λν. c is a constant =3*10^8 so frequency is equal to
(3*10^8)/0.135*10^-9. Then use ur frequency in the eqn above using h 6.626*10^-34
we will calculate pH of nitric acid of 0.1 M concentration. So, concentration of hydrogen ions in HNO3 is 0.1 M. And now by using this formula we will find pOH. So, from this we can say that pH of HNO3 is 1 and pOH of HNO3 is 13.
Please provide more of the question so I am able to answer, but I do know that H20 has 0 calories.