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zepelin [54]
3 years ago
9

What is a fire blanket MOST often used for?

Chemistry
1 answer:
Brrunno [24]3 years ago
7 0
C. wrapping someone whose clothes have caught on fire
Hope this helps! :)
You might be interested in
Hey guys please help me
Anvisha [2.4K]

Answer:

Water will move out of the eggplant cells and the cells will shrink.

Explanation:

I found it on a Quizziz.

6 0
2 years ago
You want to know how many moles of gas your lungs can hold. You start off with a balloon that has 1.4 moles of gas and occupies
Mrrafil [7]

Number of moles : n₂ = 1.775 moles

<h3>Further explanation</h3>

Given

Moles = n₁ = 1.4

Volume = V₁=22.4 L

V₂=28.4 L

Required

Moles-n₂

Solution

Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

The ratio of gas volume will be equal to the ratio of gas moles

\tt \dfrac{V_1}{V_2}=\dfrac{n_1}{n_2}

Input the values :

n₂ = (V₂ x n₁)/V₁

n₂ = (28.4 x 1.4)/22.4

n₂ = 1.775 moles

4 0
3 years ago
Complete the nuclear equation
allsm [11]
In order to solve this question, we must apply the conservation of mass. The total number of nucleons (upper number) and protons (lower number) must be equal before and after the decay. The new nucleon number is
218 - 4
= 214
And new proton number is
84 - 2
= 82
Next, we must identify which element has the proton number 82. That would be lead, Pb.
Therefore, the answer is 
5. ²¹⁴Pb₈₂
5 0
3 years ago
Can a substance be a lewis acid without being a bronsted-lowry acid?argue
storchak [24]

Answer:

Yes

Explanation:

Yes, A substance can be a lewis acid without being a Bronsted-Lowery acid because there are some substances which cannot donate protons(Bronsted-Lowery acid) but can accept a pair of electron.

<u><em>For Example:</em></u>

Let us take the example of BF₃

BF₃ contains no proton so it is not a Bronsted Lowery Acid

However, BF₃ has an incomplete octet with 6 electrons. It needs an electron pair to complete its octet. It accepts a pair of electron to become a Lewis Acid

6 0
3 years ago
Read 2 more answers
The complete combustion of a sample of propane produced 2.641 grams of carbon dioxide and 1.442 grams of water as the only produ
ohaa [14]
A general equation for a combustion reaction would be expressed as follows:

CxHy + (x+y/2)O2 = xCO2 + y/2H2O

Propane would obviously would only have carbon and hydrogen in its structure. Assuming a complete combustion, all of the carbon atoms would go to carbon dioxide and all of the hydrogen atoms to water. To determine the empirical, we determine the number of carbon and hydrogen atoms present.

moles C = 2.461 g CO2 ( 1 mol / 44.01 g ) ( 1 mol C / 1 mol CO2 ) = 0.06 mol C

moles H = 1.442 g H2O ( 1 mol / 18.02 g ) ( 2 mol H / 1 mol H ) = 0.16 mol H

Then, we divide the smallest amount to the each mole of the atoms. We do as follows:

C = 0.06 / 0.06 = 1
H = 0.16 / 0.06 = 2.67

Then we multiply a number in order to obtain a whole number ratio between the atoms.

1        CH2.67
2       C2H5.34
3       C3H8   <-------- empirical formula
8 0
3 years ago
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