Complete question is;
The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. The specific heat capacity of a certain substance has been measured to be 3.52 J/g°C. Suppose 420.0 g of the substance is heated until the temperature of the sample has changed by 43.8 °C.
Write an equation that will let you calculate the last Q that was needed for this temperature change. Your equation should contain only symbols. Be sure to define each symbol.
Answer:
Q = m•c•Δt
Q = 64753.92 J
Explanation:
We are given;
Mass (m) = 420 g
Change in temperature; (Δt) = 43.8 °C
Specific heat capacity (c) = 3.52 J/g °C
The last Q is simply the heat energy that caused that temperature change.
This is given by the formula;
Q = m•c•Δt
Plugging in the relevant values;
Q = 420 × 3.52 × 43.8
Q = 64753.92 J
Answer: There are 
oxide ions
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the moles, we use the equation:
1 mole of TiO contains = oxide ions
Thus 0.0086 moles of TiO contains = 
oxide ions
There are oxide ions
Im sorry really dont know the answer
Answer:1962kJ
Explanation:
m=2000 kg
h=100m
G=9.81m/s²
GPE=m*G*h
GPE=2000kg*100m*9.81m/s²=1,962,000J=1962 kJ
Answer:
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Explanation:
