Answer:
H2CO3(aq) ⇆ H2O(l) + CO2(g)
Explanation:
Step 1: Data given
Aqueous carbonic acid = H2CO3
H2CO3 decomposes into CO2 and H2O
Step 2: Balancing the equation
H2CO3(aq) ⇆ H2O(l) + CO2(g)
We do not have to change anything in this reaction since it's already balanced.
We have 2x H on both sides ( 2x in H2CO3 and 2x in H2O)
We have 1x C on both sides (1x in H2CO3 and 1x in CO2)
We have 3x O on both sides (3x in H2CO3 and 1x in H2O, 2x in CO2)
