Aluminum hydroxide 
can behave as a base and neutralize sulfuric acid 
as in the following equation:
(Balanced)
(a)
. Thus the ratio between the number of moles of the two reactants available:
![n(\text{Al}(\text{OH})_3, \text{supplied}) / n(\text{H}_2\text{SO}_4, \text{supplied})\\= [m(\text{Al}(\text{OH})_3)/ M(\text{Al}(\text{OH})_3)] / [n(\text{H}_2\text{SO}_4) / M(\text{H}_2\text{SO}_4)]\\= [23.7 / (26.98 + 3 \times(16.00 + 1.008))]/[29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00)]\\\approx 1.01](https://tex.z-dn.net/?f=n%28%5Ctext%7BAl%7D%28%5Ctext%7BOH%7D%29_3%2C%20%5Ctext%7Bsupplied%7D%29%20%2F%20n%28%5Ctext%7BH%7D_2%5Ctext%7BSO%7D_4%2C%20%5Ctext%7Bsupplied%7D%29%5C%5C%3D%20%5Bm%28%5Ctext%7BAl%7D%28%5Ctext%7BOH%7D%29_3%29%2F%20M%28%5Ctext%7BAl%7D%28%5Ctext%7BOH%7D%29_3%29%5D%20%2F%20%5Bn%28%5Ctext%7BH%7D_2%5Ctext%7BSO%7D_4%29%20%2F%20M%28%5Ctext%7BH%7D_2%5Ctext%7BSO%7D_4%29%5D%5C%5C%3D%20%5B23.7%20%2F%20%2826.98%20%2B%203%20%5Ctimes%2816.00%20%2B%201.008%29%29%5D%2F%5B29.5%20%2F%20%282%20%5Ctimes%201.008%20%2B%2032.07%20%2B%204%20%5Ctimes%2016.00%29%5D%5C%5C%5Capprox%201.01)
The value of this ratio required to lead to a complete reaction is derived from coefficients found in the balanced equation:
The ratio for the complete reaction is smaller than that of the reactants available, indicating that the species represented on the numerator, , is in excess while the one on the denominator, , serves as the limiting reagent.
(b)
The quantity of water produced is dependent on the amount of limiting reactants available. 
of sulfuric acid is supplied in this reaction as the limiting reagent. 
moles of water molecules are produced for every 
moles of sulfuric acid consumed. The reaction would thus give rise to 
of water molecules, which have a mass of 
.
(c)
(d)
The quantity of , the reactant in excess, is dependent on the number of moles of this species consumed in the reaction and thus the quantity of the limiting reagent available. The consumption of every moles of sulfuric acid, the limiting reagent, removes 
moles of aluminum hydroxide from the solution. 
of sulfuric acid is initially available as previously stated such that 
, or 
, of would be eventually consumed.
of would thus be in excess by the end of the reaction process.
Answer:
Removing the worms is they first key to overcoming this problem. Thus you should ensure that the worms have not spread throughout the house/facility, or caused more damage.
Secondly, you should replace the pipes taht the worms got into, or clean them at most. If it’s simply worm droppings then just clean it, but if it’s more and worse than that alike slime then it is best to remove and replace it.
the only way the worms escaping could affect something is if they decontaminated it, or alas ate or destroyed it. Other than that if they died you could simply replace them, but e things cannot be replaced
Explanation:
You didn’t actually tell us any details so that the best I got from that
can I have brainlest pwease?
Answer:
Flood barriers
Explanation:
Many towns in flood-prone areas are surrounded by flood barriers that are built to hold back rising water during seasonal highs.
- Flood barriers are water resistant walls that are used to prevent breaking water during a high period of inundation from their channels.
- They are usually vertical artificial structures which can be temporary or permanent.
- They help to hold or contain the flood water during the high season.
- These walls prevents flood plains and other nearby areas from getting flooded during the rainy season.
Answer:
Explanation:
Hello!
In this case, considering the partial Dalton's law of partial pressures, we can notice that the total pressure equals the pressure of steam and the pressure of hydrogen, which can be determined as shown below:
Thus, by using the ideal gas law, we can compute the moles of hydrogen as shown below:
Best regards!
This is the equation balanced:
<span>BaCl2(aq) + Na2CO3(aq) = BaCO3(s) + 2 NaCl(aq)
Then the coefficient in front of Na Cl is 2.
Answer: 2
</span>
