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3 years ago

Question is 15 points

Mathematics

1 answer:

Blababa [14]3 years ago

7 0

sin(x+y)=sin(x)cos(y)-cos(x)sin(y)

also, remember pythagorean rule, $sin^2(x)+cos^2(x)=1$

given that sin(Θ)=4/5 and cos(x)=-5/13

find sin(x) and cos(Θ)

sin(x)

cos(x)=-5/13

using pythagorean identity

(sin(x))^2+(-5/13)^2=1

sin(x)=+/- 12/13

in the 2nd quadrant, sin is positve so sin(x)=12/13

cos(Θ)

sin(Θ)=4/5

using pythagrean identity

(4/5)^2+(cos(Θ))^2=1

cos(Θ)=+/-3/5

in 1st quadrant, cos is positive

cos(Θ)=3/5

so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)

sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)

sin(Θ+x)=16/65

answer is 1st option

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Answer:

70° and 110°

Step-by-step explanation:

It is given that, two parallel lines l and m are intersected by a transversal t.

The interior angles on same side of transversal are (2x−8)° and (3x−7)°.

We need to find the measure of these angles.

We know that, the sum of interior angles of the same side of the transversal is equal to 180°. So,

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3 years ago

Please help me with this problem

AleksandrR [38]

Answer:

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Step-by-step explanation:

Process

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