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Sergeeva-Olga [200]

3 years ago

7

What is the answer plz help.

1 answer:

Dima020 [189]3 years ago

4 0

Answer:

0.2

Step-by-step explanation:

C.O.P-the constant value of the ratio of two proportional quantities x and y, typically the equation is Y=KX.

So to find that you would divide y by x.

In this case the dot is between 0 and 2 on y so it is 1 and between 4 and 6 on x so it is 5.

Then you would divide 1/5 and get 0.2 or you could look at the end of the graph and notice that the last point is at (10,2) and divide 2/10 and get the same thing.

HOPE THIS HELPS!!!

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tatuchka [14]

Answer:

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$t_{2} = 1.422\pi \pm \pi\cdot i$ , $\forall \,i \in \mathbb{N}_{O}$

Step-by-step explanation:

In the case of parametric equations, the slope of the curve is equal to:

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

Where $\frac{dx}{dt}$ and $\frac{dy}{dt}$ are the first derivatives of $x$ and $y$ regarding $t$ . Let be $x(t) =2\cdot \cos t$ and $y(t) = 8\cdot \sin t$ , their first derivatives are found:

$\frac{dx}{dt} = -2\cdot \sin t$ and $\frac{dy}{dt} = 8\cdot \cos t$

Thus, equation for the slope is:

$\frac{dy}{dx} = -\frac{8\cdot \cos t}{2\cdot \sin t}$

$\frac{dy}{dx} = -\frac{4}{\tan t}$

If $\frac{dy}{dx} = -1$ , then:

$-1 = -\frac{4}{\tan t}$

$\tan t = 4$

Tangent is positive at 1st quadrant and is a function with a periodicity of $\pi$ , the set of solutions are:

$t_{1} = 0.422\pi \pm \pi\cdot i$ , $\forall \,i \in \mathbb{N}_{O}$

$t_{2} = 1.422\pi \pm \pi\cdot i$ , $\forall \,i \in \mathbb{N}_{O}$

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timama [110]

The answer is b. Hope this helped

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Step-by-step explanation:

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