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vampirchik [111]
3 years ago
8

Whats the reciprocal to 2 3/8?

Mathematics
2 answers:
almond37 [142]3 years ago
5 0

Answer:

8/19

Step-by-step explanation:

Given x, the reciprocal is 1/x.

Given 2 3/8, we first rewrite this as an improper fraction:  19/8, and then invert this result:  8/19

ICE Princess25 [194]3 years ago
4 0

Answer:

8/19 would be the answer to this question.

I hope this helped you! :)

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2+2 my question must be 20 characters long
geniusboy [140]
It is four. So two and two you add them together to be four. Good job. Your learning :)
4 0
3 years ago
In measuring the center of the data from a skewed distribution, the median would be preferred over the mean for most purposes be
icang [17]
<span>The median would be preferred over the mean in such scenarios because the median will lessen the impact of the outliers that fall within the "tail" of the skew. Therefore, if a curve is normally distributed, that is to say that data is normally distributed, there will be two tails, each with approximately equal proportions of outliers. Outliers in this case being more extreme numbers, and are based on your determination depending on how you are using the data. If data is skewed there is one tail, and therefore it may be an inaccurate measure of central tendency if you use the mean of the numbers. Thinking of this visually. In positively skewed data where there is a "tail" towards the right and a "peak" towards the left, the median will be placed more in the "peak", whereas the mean will be placed more towards the "tail", making it a poorer measure of central tendency, or the center of the data.</span>
5 0
3 years ago
Find the distance between (3,4) and (4,-6) if necessary, round to the nearest tenth.
Ratling [72]

Answer:

The distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

Step-by-step explanation:

Given the points

  • (3,4)
  • (4,-6)

The distance 'd' between (3,4) and (4,-6)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

substituting the points values

   =\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}

   =\sqrt{1+10^2}

   =\sqrt{1+100}

   =\sqrt{101}

   =10.0  units (Rounded to the nearest the Tenths Place)

Thus, the distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

4 0
3 years ago
At a school for performance art students 2
gtnhenbr [62]

Answer:

i need help with this too

Step-by-step explanation:

3 0
3 years ago
Rectangle ABCD was dilated to create rectangle A'B'C'D. Triangle A B C D is dilated to form triangle A prime B prime C prime D.
Julli [10]

Answer:

AB = 6

Step-by-step explanation:

Given

BC = 3.8

A'B' = 15

B'C' = 9.5

Required

Determine the length of AB

Because A'B'C'D is a dilation of ABCD, then the following relationship must exist:

A'B' : AB = B'C' : BC

Substitute values for A'B', B'C' and BC

15 : AB = 9.5 : 3.8

Express the ratio as fractions:

\frac{AB}{15} = \frac{3.8}{9.5}

Multiply through by 14

15 * \frac{AB}{15} = \frac{3.8}{9.5} * 15

AB = \frac{3.8}{9.5} * 15

AB = \frac{3.8* 15}{9.5}

AB = \frac{57}{9.5}

AB = 6

8 0
3 years ago
Read 2 more answers
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