Answer:
1
Step-by-step explanation:
I believe the answer would 5 blocks
If you go 3 blocks East and 4 north, they are like the straight sides of a triangle, so to find the diagonal distance, or the shortest distance, you would find the diagonal side of a triangle it is
A squared + B squared = C squared
So 3x3 = 9
And 4x4 = 16
16+9=25
And the square root of 25 is 5
Please correct me if I am wrong and have a good day
Answer:
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
![\mu = 96, \sigma = 15.7](https://tex.z-dn.net/?f=%5Cmu%20%3D%2096%2C%20%5Csigma%20%3D%2015.7)
Probability that a randomly selected adult has an IQ greater than 123.4.
This is 1 subtracted by the pvalue of Z when X = 123.4. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{123.4 - 96}{15.7}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B123.4%20-%2096%7D%7B15.7%7D)
![Z = 1.745](https://tex.z-dn.net/?f=Z%20%3D%201.745)
has a pvalue of 0.9595
1 - 0.9595 = 0.0405
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Answer:
the fraction can be write as 7/8
3/4=6/8
6/8+1/8=7/8
Step-by-step explanation:
here is your answer if you like my answer please follow
Answer:
The correct option is;
ΔCED ~ ΔCAB
Step-by-step explanation:
Given that the translation maps angle ∠D to angle ∠B, we have;
Angle ∠D is congruent to ∠B (Given)
Segment ED is parallel to segment AB (lines having similar angles to a common transversal)
Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)
∠C is congruent to ∠C reflexive property
Therefore, we have;
∠C ≅ ∠C
∠E ≅ ∠A
∠D ≅ ∠B
Which gives ΔCED is similar to ΔCAB (not ΔCBA)