Increase £30 by 2/5?

Jane read 3/8 of a book for 6 days. How many books did she read?

otez555 [7]

$Hey$ $there!$

$The$ $answer$ $to$ $your$ $question$ $is$ $2 \frac{1}{4}$ $books$ .

$To$ $solve$ $this$ , $we$ $must$ $multiply$ $\frac{3}{8}$ $by$ $6$

$\frac{3}{8} *\frac{6}{1}=\frac{18}{8} =2\frac{1}{4}$

$Hope$ $it$ $helps!$ $Have$ $a$ $great$ $day!$

7 0

2 years ago

Slove system of equation. 2x - 6y = 8 -3x + 9y = 12

Bond [772]

Answers:

2x - 6y = 8 -> x = 4 + 3y

-3x + 9y = 12 -> x = -4 + 3y

7 0

1 year ago

Youre purchasing a new television with a 32" screen. the 32" measurement represents the diagonal measurement of the screen. You

Nonamiya [84]

Answer:

B. 28 inches

Step-by-step explanation:

We can use the Pythagorean theorem to solve this problem.

a^2 +b^2 =c^2 where a and b are the legs and c is the hypotenuse (diagonal)

16^2 + b^2 = 32^2

256 + b^2 =1024

Subtract 256 from each side

256-256 + b^2 =1024-256

b^2 = 768

Take the square root of each side

sqrt(b^2) = sqrt(768)

b = 27.7128129

Rounding to the nearest inche

b = 28 inches

3 0

2 years ago

Please help with geometry. 20 points, and another question worth 98 on my profile!

vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) $PR^{2} =PS*PT$

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The Intersecting Secant-Tangent Theorem, states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

$PR^{2} =PS*PT$

Part 3)

we know that

The Tangent-Tangent Theorem states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

4 0

2 years ago

More solving quadratic equations: the quadratic formula again, what we've all been waiting for. the quadratic formula is pretty

kirill [66]

You don't have a question in there but I can tell you that the quadratic formula that is shown is not quite correct.
x = -b ± √b2 - 4ac 2a
For one thing, the first 3 terms should ALL be divided by 2a
The square root symbol should be extended from b^2 through 4ac
The division symbol is missing.
So the quadratic formula SHOULD read:
x = [-b +- sq root (b^2 - 4ac) ] / 2a
Also I have attached a graphic of the quadratic formula.

5 0

2 years ago